基于Python的多个列表存在项目数据合并

前言

? ? ? ? 在做项目的时候，经常会遇到一个大列表中存在多个小列表，然后小列表中有很多相同的值，需要对存在相同的值的列进行合并去重。

如题：

lists = [
    [0, 1, 2],
    [6, 7],
    [3, 4, 5],
    [3, 6, 7],
    [8, 9, 10],
    [23, 24, 25],
    [10, 11, 12],
    [13, 14, 15],
    [15, 16, 17],
    [2, 3],
    [20],
]

解决思路

思路一

先遍历，先找出没个元素出现在列表中的索引，再遍历存在索引值就进行数据合并

list_dict = {}
for i, item in enumerate(lists):
    for e in item:
        if e in list_dict:
            if i not in list_dict[e]:
                list_dict[e].append(i)
        else:
            list_dict[e] = [i]

merge_idx_list = []
element_set = set()
index_set = set()
for e, tmp_list in list_dict.items():
    if e in element_set:
        continue
    element_set.add(e)
    cursor = 0
    queue_list = []
    for idx in tmp_list:
        if idx not in index_set:
            index_set.add(idx)
            queue_list.append(idx)
    while cursor < len(queue_list):
        l_idx = queue_list[cursor]
        for ee in lists[l_idx]:
            if ee in element_set:
                continue
            element_set.add(ee)
            cand_list = list_dict[ee]
            for cand_idx in cand_list:
                if cand_idx not in index_set:
                    index_set.add(cand_idx)
                    queue_list.append(cand_idx)
        cursor += 1
    merge_idx_list.append(queue_list)

print(merge_idx_list)


result_list = []
for idx_list in merge_idx_list:
    union_set = set()
    for idx in idx_list:
        union_set = union_set.union(set(lists[idx]))
    result_list.append(union_set)

print(result_list)

结果：

[[0, 9, 2, 3, 1], [4, 6], [5], [7, 8], [10]]

[{0, 1, 2, 3, 4, 5, 6, 7}, {8, 9, 10, 11, 12}, {24, 25, 23}, {16, 17, 13, 14, 15}, {20}]

完毕！！！