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题目链接:435. 无重叠区间 - 力扣(LeetCode)
代码如下:
class Solution {
public:
static bool cmp(vector<int>&a,vector<int>&b){
return a[0]<b[0];
}
int eraseOverlapIntervals(vector<vector<int>>& intervals) {
int count=1;
sort(intervals.begin(),intervals.end(),cmp);
for(int i=1;i<intervals.size();i++){
if(intervals[i-1][1]<=intervals[i][0])count++;
else intervals[i][1]=min(intervals[i-1][1],intervals[i][1]);
}
return intervals.size()-count;
}
};
题目链接:763. 划分字母区间 - 力扣(LeetCode)
代码如下
class Solution {
public:
vector<int> partitionLabels(string s) {
vector<int>res;
int left=0;
int right=0;
int hash[26];
for(int i=0;i<s.size();i++)hash[s[i]-'a']=i;
for(int i=0;i<s.size();i++){
right=max(right,hash[s[i]-'a']);
if(i==right){
res.push_back(right-left+1);
left=i+1;
}
}
return res;
}
};
解题代码如下:
class Solution {
public:
static bool cmp(vector<int>&a,vector<int>&b){
return a[0]<b[0];
}
vector<vector<int>> merge(vector<vector<int>>& intervals) {
int left=0;
int right=0;
vector<vector<int>>res;
sort(intervals.begin(),intervals.end(),cmp);
// sort(intervals.begin(), intervals.end(), [](const vector<int>& a, const vector<int>& b){return a[0] < b[0];});
res.push_back(intervals[0]);
for(int i=1;i<intervals.size();i++){
if(res.back()[1]<intervals[i][0])res.push_back(intervals[i]);
else{
res.back()[1]=max(res.back()[1],intervals[i][1]);
}
}
return res;
}
};