文章链接:代码随想录
视频链接:LeetCode:435.无重叠区间
题目链接:力扣题目链接
图释:
class Solution {
public:
static bool cmp(const vector<int>&a, const vector<int>&b){
return a[0] < b[0];
}
int eraseOverlapIntervals(vector<vector<int>>& intervals) {
// if(intervals.size() == 0 ||intervals.size() ==1) return 0;
sort(intervals.begin(), intervals.end(),cmp);
int result = 0;
for(int i=1; i<intervals.size(); i++){
if(intervals[i-1][1]>intervals[i][0]){
result++;
intervals[i][1] = min(intervals[i-1][1], intervals[i][1]);
}
}
return result;
}
};
文章链接:代码随想录
视频链接:LeetCode:763.划分字母区间
题目链接:力扣题目链接
图释:
class Solution {
public:
vector<int> partitionLabels(string s) {
int hash[27]={0};
for(int i=0; i<s.size(); i++){
// s[i]-'a' ask||码,对应下标
hash[s[i]-'a'] = i; // 反复更新最远距离
}
vector<int> result;
int left = 0, right = 0;
for(int i=0; i<s.size(); i++){
right = max(right, hash[s[i]-'a']); // 每经过一格更新一下最远距离
if(i==right){
result.push_back(right-left+1);
left = i+1;
}
}
return result;
}
};
文章链接:代码随想录
视频链接:LeetCode:56.合并区间
题目链接:力扣题目链接
图释:
class Solution {
public:
static bool cmp(const vector<int>&a, const vector<int>&b){
return a[0]<b[0];
}
vector<vector<int>> merge(vector<vector<int>>& intervals) {
if(intervals.size()<=1) return intervals;
vector<vector<int>> result;
vector<int> path;
sort(intervals.begin(), intervals.end(), cmp);
path.push_back(intervals[0][0]);
for(int i=1; i<intervals.size(); i++){
if(intervals[i-1][1] >= intervals[i][0]){
// 更新右边边界
intervals[i][1] = max(intervals[i][1], intervals[i-1][1]);
}else{//没有重叠
path.push_back(intervals[i-1][1]);
result.push_back(path);
path.clear();
path.push_back(intervals[i][0]);
}
}
path.push_back(intervals[intervals.size()-1][1]);
result.push_back(path);
return result;
}
};