16.综合项目实战

发布时间:2023年12月31日

一、基础演练:

1、建库、建表

# 创建数据库

create database mysql_exampleTest;

use mysql_exampleTest;

# 学生表

CREATE TABLE Student(

s_id VARCHAR(20),

s_name VARCHAR(20) NOT NULL DEFAULT '',

s_birth VARCHAR(20) NOT NULL DEFAULT '',

s_sex VARCHAR(10) NOT NULL DEFAULT '',

PRIMARY KEY(s_id)

);

# 课程表

CREATE TABLE Course(

c_id VARCHAR(20),

c_name VARCHAR(20) NOT NULL DEFAULT '',

t_id VARCHAR(20) NOT NULL,

PRIMARY KEY(c_id)

);

# 教师表

CREATE TABLE Teacher(

t_id VARCHAR(20),

t_name VARCHAR(20) NOT NULL DEFAULT '',

PRIMARY KEY(t_id)

);

# 成绩表

CREATE TABLE Score(

s_id VARCHAR(20),

c_id VARCHAR(20),

s_Score INT(3),

PRIMARY KEY(s_id,c_id)

);

2、插入数据:

# 插入学生表测试数据

insert into Student values('01' , '赵雷' , '1990-01-01' , '男');

insert into Student values('02' , '钱电' , '1990-12-21' , '男');

insert into Student values('03' , '孙风' , '1990-05-20' , '男');

insert into Student values('04' , '李云' , '1990-08-06' , '男');

insert into Student values('05' , '周梅' , '1991-12-01' , '女');

insert into Student values('06' , '吴兰' , '1992-03-01' , '女');

insert into Student values('07' , '郑竹' , '1989-07-01' , '女');

insert into Student values('08' , '王菊' , '1990-01-20' , '女');

Student表:

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

| 05 | 周梅 | 1991-12-01 | 女 |

| 06 | 吴兰 | 1992-03-01 | 女 |

| 07 | 郑竹 | 1989-07-01 | 女 |

| 08 | 王菊 | 1990-01-20 | 女 |

+------+--------+------------+-------+

# 课程表测试数据

insert into Course values('01' , '语文' , '02');

insert into Course values('02' , '数学' , '01');

insert into Course values('03' , '英语' , '03');

Course表:

+------+--------+------+

| c_id | c_name | t_id |

+------+--------+------+

| 01 | 语文 | 02 |

| 02 | 数学 | 01 |

| 03 | 英语 | 03 |

+------+--------+------+

# 教师表测试数据

insert into Teacher values('01' , '张三');

insert into Teacher values('02' , '李四');

insert into Teacher values('03' , '王五');

Teacher表:

+------+--------+

| t_id | t_name |

+------+--------+

| 01 | 张三 |

| 02 | 李四 |

| 03 | 王五 |

+------+--------+

# 成绩表测试数据

insert into Score values('01' , '01' , 80);

insert into Score values('01' , '02' , 90);

insert into Score values('01' , '03' , 99);

insert into Score values('02' , '01' , 70);

insert into Score values('02' , '02' , 60);

insert into Score values('02' , '03' , 80);

insert into Score values('03' , '01' , 80);

insert into Score values('03' , '02' , 80);

insert into Score values('03' , '03' , 80);

insert into Score values('04' , '01' , 50);

insert into Score values('04' , '02' , 30);

insert into Score values('04' , '03' , 20);

insert into Score values('05' , '01' , 76);

insert into Score values('05' , '02' , 87);

insert into Score values('06' , '01' , 31);

insert into Score values('06' , '03' , 34);

insert into Score values('07' , '02' , 89);

insert into Score values('07' , '03' , 98);

Score表:

+------+------+---------+

| s_id | c_id | s_Score |

+------+------+---------+

| 01 | 01 | 80 |

| 01 | 02 | 90 |

| 01 | 03 | 99 |

| 02 | 01 | 70 |

| 02 | 02 | 60 |

| 02 | 03 | 80 |

| 03 | 01 | 80 |

| 03 | 02 | 80 |

| 03 | 03 | 80 |

| 04 | 01 | 50 |

| 04 | 02 | 30 |

| 04 | 03 | 20 |

| 05 | 01 | 76 |

| 05 | 02 | 87 |

| 06 | 01 | 31 |

| 06 | 03 | 34 |

| 07 | 02 | 89 |

| 07 | 03 | 98 |

+------+------+---------+

3、实战查询50例

# 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

# 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

# 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

# 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)

# 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

# 6、查询"李"姓老师的数量

# 7、查询学过"张三"老师授课的同学的信息

# 8、查询没学过"张三"老师授课的同学的信息

# 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

# 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

# 11、查询没有学全所有课程的同学的信息

# 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息

# 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息

# 14、查询没学过"张三"老师讲授的任一门课程的学生姓名

# 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩

# 16、检索"01"课程分数小于60,按分数降序排列的学生信息

# 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩,可加round,case when t

# 18.查询各科成绩最高分、最低分和平均分:

以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率

及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

# 19、按各科成绩进行排序,并显示排名(实现不完全)

# 20、查询学生的总成绩并进行排名

# 21、查询不同老师所教不同课程平均分从高到低显示

# 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

# 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0]及所占百分比

# 24、查询学生平均成绩及其名次

# 25、查询各科成绩前三名的记录

# 26、查询每门课程被选修的学生数

# 27、查询出只有两门课程的全部学生的学号和姓名

# 28、查询男生、女生人数

# 29、查询名字中含有"风"字的学生信息

# 30、查询同名同性学生名单,并统计同名人数

# 31、查询1990年出生的学生名单

# 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

# 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

# 34、查询课程名称为"数学",且分数低于60的学生姓名和分数

# 35、查询所有学生的课程及分数情况;

# 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数

# 37、查询不及格的课程

# 38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名

# 39、求每门课程的学生人数

# 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩

# 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

# 42、查询每门功成绩最好的前两名

# 43、统计每门课程的学生选修人数(超过5人的课程才统计)。

要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

# 44、检索至少选修两门课程的学生学号

# 45、查询选修了全部课程的学生信息

# 46、查询各学生的年龄(实岁)

# 47、查询本周过生日的学生

# 48、查询下周过生日的学生(还要排除闰年情况)

# 49、查询本月过生日的学生

# 50、查询下月过生日的学生

================================参考答案================================

# 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

select st.*,sc.s_Score as '语文' ,sc2.s_Score '数学'

from Student st

left join Score sc on sc.s_id=st.s_id and sc.c_id='01'

left join Score sc2 on sc2.s_id=st.s_id and sc2.c_id='02'

where sc.s_Score>sc2.s_Score;

+------+--------+------------+-------+------+------+

| s_id | s_name | s_birth | s_sex | 语文 | 数学 |

+------+--------+------------+-------+------+------+

| 02 | 钱电 | 1990-12-21 | 男 | 70 | 60 |

| 04 | 李云 | 1990-08-06 | 男 | 50 | 30 |

+------+--------+------------+-------+------+------+

# 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

select st.*,sc.s_Score '语文',sc2.s_Score '数学' from Student st

left join Score sc on sc.s_id=st.s_id and sc.c_id='01'

left join Score sc2 on sc2.s_id=st.s_id and sc2.c_id='02'

where sc.s_Score<sc2.s_Score;

+------+--------+------------+-------+------+------+

| s_id | s_name | s_birth | s_sex | 语文 | 数学 |

+------+--------+------------+-------+------+------+

| 01 | 赵雷 | 1990-01-01 | 男 | 80 | 90 |

| 05 | 周梅 | 1991-12-01 | 女 | 76 | 87 |

+------+--------+------------+-------+------+------+

# 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

select st.s_id,st.s_name,ROUND(AVG(sc.s_Score),2) cjScore from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id having AVG(sc.s_Score)>=60;

+------+--------+---------+

| s_id | s_name | cjScore |

+------+--------+---------+

| 01 | 赵雷 | 89.67 |

| 02 | 钱电 | 70.00 |

| 03 | 孙风 | 80.00 |

| 05 | 周梅 | 81.50 |

| 07 | 郑竹 | 93.50 |

+------+--------+---------+

# 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)

select st.s_id,st.s_name,(case when ROUND(AVG(sc.s_Score),2) is null then 0 else ROUND(AVG(sc.s_Score)) end ) cjScore from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id having AVG(sc.s_Score)<60 or AVG(sc.s_Score) is NULL;

+------+--------+---------+

| s_id | s_name | cjScore |

+------+--------+---------+

| 04 | 李云 | 33 |

| 06 | 吴兰 | 33 |

| 08 | 王菊 | 0 |

+------+--------+---------+

# 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

select st.s_id,st.s_name,count(sc.c_id) '选课总数',(case when sum(sc.s_Score) is null or sum(sc.s_Score)='' then 0 else sum(sc.s_Score) end) '总成绩'

from Student st

left outer join Score sc on st.s_id=sc.s_id

group by st.s_id;

+------+--------+----------+--------+

| s_id | s_name | 选课总数 | 总成绩 |

+------+--------+----------+--------+

| 01 | 赵雷 | 3 | 269 |

| 02 | 钱电 | 3 | 210 |

| 03 | 孙风 | 3 | 240 |

| 04 | 李云 | 3 | 100 |

| 05 | 周梅 | 2 | 163 |

| 06 | 吴兰 | 2 | 65 |

| 07 | 郑竹 | 2 | 187 |

| 08 | 王菊 | 0 | 0 |

+------+--------+----------+--------+

# 6、查询"李"姓老师的数量

select t.t_name,count(t.t_id) from Teacher t

group by t.t_id having t.t_name like "李%";

+--------+----------+

| t_name | count(*) |

+--------+----------+

| 李四 | 1 |

+--------+----------+

# 7、查询学过"张三"老师授课的同学的信息

select st.* from Student st

left join Score sc on sc.s_id=st.s_id

left join Course c on c.c_id=sc.c_id

left join Teacher t on t.t_id=c.t_id

where t.t_name="张三";

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

| 05 | 周梅 | 1991-12-01 | 女 |

| 07 | 郑竹 | 1989-07-01 | 女 |

+------+--------+------------+-------+

# *8、查询没学过"张三"老师授课的同学的信息

-- 张三老师教的课

select c.* from Course c left join Teacher t on t.t_id=c.t_id where t.t_name="张三"

-- 有张三老师课成绩的st.s_id

select sc.s_id from Score sc where sc.c_id in (select c.c_id from Course c left join Teacher t on t.t_id=c.t_id where t.t_name="张三")

-- 不在上面查到的st.s_id的学生信息,即没学过张三老师授课的同学信息

select st.* from Student st where st.s_id not in(

select sc.s_id from Score sc where sc.c_id in (select c.c_id from Course c left join Teacher t on t.t_id=c.t_id where t.t_name="张三")

)

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 06 | 吴兰 | 1992-03-01 | 女 |

| 08 | 王菊 | 1990-01-20 | 女 |

+------+--------+------------+-------+

# *9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

select st.* from Student st

inner join Score sc on sc.s_id = st.s_id

inner join Course c on c.c_id=sc.c_id and c.c_id="01"

where st.s_id in (

select st2.s_id from Student st2

inner join Score sc2 on sc2.s_id = st2.s_id

inner join Course c2 on c2.c_id=sc2.c_id and c2.c_id="02"

)

select st.*

from Student st

inner join Score s on st.s_id = s.s_id and s.c_id = '01'

inner join Score s2 on st.s_id=s2.s_id and s2.c_id='02';

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

| 05 | 周梅 | 1991-12-01 | 女 |

+------+--------+------------+-------+

# 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

select st.* from Student st

inner join Score sc on sc.s_id = st.s_id

inner join Course c on c.c_id=sc.c_id and c.c_id="01"

where st.s_id not in (

select st2.s_id from Student st2

inner join Score sc2 on sc2.s_id = st2.s_id

inner join Course c2 on c2.c_id=sc2.c_id and c2.c_id="02"

);

select st.* from Student st

inner join Score sc on sc.s_id = st.s_id and sc.c_id="01"

where st.s_id not in (

select st2.s_id from Student st2

inner join Score sc2 on sc2.s_id = st2.s_id and sc2.c_id="02"

);

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 06 | 吴兰 | 1992-03-01 | 女 |

+------+--------+------------+-------+

# 11、查询没有学全所有课程的同学的信息

select * from Student where s_id not in (

select st.s_id from Student st

inner join Score sc on sc.s_id = st.s_id and sc.c_id="01"

where st.s_id in (

select st2.s_id from Student st2

inner join Score sc2 on sc2.s_id = st2.s_id and sc2.c_id="02"

) and st.s_id in (

select st2.s_id from Student st2

inner join Score sc2 on sc2.s_id = st2.s_id and sc2.c_id="03"

));

select * from Student

where s_id not in

(select s_id from Score group by s_id having count(c_id)=(select count(*) from Course));

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 05 | 周梅 | 1991-12-01 | 女 |

| 06 | 吴兰 | 1992-03-01 | 女 |

| 07 | 郑竹 | 1989-07-01 | 女 |

| 08 | 王菊 | 1990-01-20 | 女 |

+------+--------+------------+-------+

# 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息

select distinct st.* from Student st

left join Score sc on sc.s_id=st.s_id

where sc.c_id in (

select sc2.c_id from Student st2

left join Score sc2 on sc2.s_id=st2.s_id

where st2.s_id ='01'

);

select distinct st.*

from Student st inner join Score s on st.s_id = s.s_id

where s.c_id = any (select c_id from Score where s_id = '01');

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

| 05 | 周梅 | 1991-12-01 | 女 |

| 06 | 吴兰 | 1992-03-01 | 女 |

| 07 | 郑竹 | 1989-07-01 | 女 |

+------+--------+------------+-------+

# *13、查询和"01"号的同学学习的课程完全相同的其他同学的信息

select st.* from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id

having group_concat(sc.c_id) =

(

select group_concat(sc2.c_id) from Student st2

left join Score sc2 on sc2.s_id=st2.s_id

where st2.s_id ='01'

);

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

+------+--------+------------+-------+

# 14、查询没学过"张三"老师讲授的任一门课程的学生姓名

select st.s_name from Student st

where st.s_id not in (

select sc.s_id from Score sc

inner join Course c on c.c_id=sc.c_id

inner join Teacher t on t.t_id=c.t_id and t.t_name="张三"

);

select s_name from Student

where s_id not in

(select distinct st.s_id from Student st left outer join Score s on st.s_id = s.s_id where s.c_id in

(select c_id from Course where t_id = (select t_id from Teacher where t_name = '张三')));

+--------+

| s_name |

+--------+

| 吴兰 |

| 王菊 |

+--------+

# 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩

select st.s_id,st.s_name,avg(sc.s_Score) from Student st

left join Score sc on sc.s_id=st.s_id

where sc.s_id in (

select sc.s_id from Score sc

where sc.s_Score<60 or sc.s_Score is NULL

group by sc.s_id having COUNT(sc.s_id)>=2

)

group by st.s_id;

select st.s_id, st.s_name, avg(s.s_Score)

from Student st left outer join Score s on st.s_id = s.s_id

where st.s_id in (

select s_id from Score

where s_Score < 60 or s_Score is null

group by s_id having count(s_Score) >= 2

)

group by st.s_id, st.s_name;

+------+--------+----------------+

| s_id | s_name | avg(s.s_Score) |

+------+--------+----------------+

| 04 | 李云 | 33.3333 |

| 06 | 吴兰 | 32.5000 |

+------+--------+----------------+

# 16、检索"01"课程分数小于60,按分数降序排列的学生信息

select st.*,sc.s_Score from Student st

inner join Score sc on sc.s_id=st.s_id and sc.c_id="01" and sc.s_Score<60

order by sc.s_Score desc;

select st.*, s.s_Score

from Student st inner join Score s on st.s_id = s.s_id

where s.c_id = '01' and s.s_Score < 60

order by s.s_Score desc;

+------+--------+------------+-------+---------+

| s_id | s_name | s_birth | s_sex | s_Score |

+------+--------+------------+-------+---------+

| 04 | 李云 | 1990-08-06 | 男 | 50 |

| 06 | 吴兰 | 1992-03-01 | 女 | 31 |

+------+--------+------------+-------+---------+

# 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩,可加round,case when then else end 使显示更完美

select st.s_id,st.s_name,avg(sc4.s_Score) "平均分",sc.s_Score "语文",sc2.s_Score "数学",sc3.s_Score "英语" from Student st

left join Score sc on sc.s_id=st.s_id and sc.c_id="01"

left join Score sc2 on sc2.s_id=st.s_id and sc2.c_id="02"

left join Score sc3 on sc3.s_id=st.s_id and sc3.c_id="03"

left join Score sc4 on sc4.s_id=st.s_id

group by st.s_id

order by avg(sc4.s_Score) desc;

select st.s_id, st.s_name, avg(s.s_Score) '平均成绩', s1.s_Score '语文', s2.s_Score '数学', s3.s_Score '英语'

from Student st

left outer join Score s on st.s_id = s.s_id

left outer join Score s1 on st.s_id = s1.s_id and s1.c_id = '01'

left outer join Score s2 on st.s_id = s2.s_id and s2.c_id = '02'

left outer join Score s3 on st.s_id = s3.s_id and s3.c_id = '03'

group by st.s_id, st.s_name

order by avg(s.s_Score) desc;

+------+--------+----------+------+------+------+

| s_id | s_name | 平均成绩 | 语文 | 数学 | 英语 |

+------+--------+----------+------+------+------+

| 07 | 郑竹 | 93.5000 | NULL | 89 | 98 |

| 01 | 赵雷 | 89.6667 | 80 | 90 | 99 |

| 05 | 周梅 | 81.5000 | 76 | 87 | NULL |

| 03 | 孙风 | 80.0000 | 80 | 80 | 80 |

| 02 | 钱电 | 70.0000 | 70 | 60 | 80 |

| 04 | 李云 | 33.3333 | 50 | 30 | 20 |

| 06 | 吴兰 | 32.5000 | 31 | NULL | 34 |

| 08 | 王菊 | NULL | NULL | NULL | NULL |

+------+--------+----------+------+------+------+

# *18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率

# 及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

select c.c_id,c.c_name,max(sc.s_Score) "最高分",MIN(sc2.s_Score) "最低分",avg(sc3.s_Score) "平均分"

,((select count(s_id) from Score where s_Score>=60 and c_id=c.c_id )/(select count(s_id) from Score where c_id=c.c_id)) "及格率"

,((select count(s_id) from Score where s_Score>=70 and s_Score<80 and c_id=c.c_id )/(select count(s_id) from Score where c_id=c.c_id)) "中等率"

,((select count(s_id) from Score where s_Score>=80 and s_Score<90 and c_id=c.c_id )/(select count(s_id) from Score where c_id=c.c_id)) "优良率"

,((select count(s_id) from Score where s_Score>=90 and c_id=c.c_id )/(select count(s_id) from Score where c_id=c.c_id)) "优秀率"

from Course c

left join Score sc on sc.c_id=c.c_id

left join Score sc2 on sc2.c_id=c.c_id

left join Score sc3 on sc3.c_id=c.c_id

group by c.c_id;

select c.c_id, c.c_name, max(s.s_Score) '最高分', min(s.s_Score) '最低分', avg(s.s_Score) '平均分',

(select count(s_Score)/(select count(s_Score) from Score where c_id = c.c_id )

from Score where c_id = c.c_id and s_Score >= 60) '及格率',

(select count(s_Score)/(select count(s_Score) from Score where c_id = c.c_id )

from Score where c_id = c.c_id and (s_Score between 70 and 79)) '中等率',

(select count(s_Score)/(select count(s_Score) from Score where c_id = c.c_id )

from Score where c_id = c.c_id and (s_Score between 80 and 89)) '优良率',

(select count(s_Score)/(select count(s_Score) from Score where c_id = c.c_id )

from Score where c_id = c.c_id and s_Score >= 90) '优秀率'

from Course c left outer join Score s on c.c_id = s.c_id

group by c.c_id, c.c_name;

+------+--------+--------+--------+---------+--------+--------+--------+--------+

| c_id | c_name | 最高分 | 最低分 | 平均分 | 及格率 | 中等率 | 优良率 | 优秀率 |

+------+--------+--------+--------+---------+--------+--------+--------+--------+

| 01 | 语文 | 80 | 31 | 64.5000 | 0.6667 | 0.3333 | 0.3333 | 0.0000 |

| 02 | 数学 | 90 | 30 | 72.6667 | 0.8333 | 0.0000 | 0.5000 | 0.1667 |

| 03 | 英语 | 99 | 20 | 68.5000 | 0.6667 | 0.0000 | 0.3333 | 0.3333 |

+------+--------+--------+--------+---------+--------+--------+--------+--------+

# *19、按各科成绩进行排序,并显示排名(实现不完全)

# mysql没有rank函数

# 加@Score是为了防止用union all 后打乱了顺序

select c1.s_id,c1.c_id,c1.c_name,@Score:=c1.s_Score,@i:=@i+1 from (select c.c_name,sc.* from Course c

left join Score sc on sc.c_id=c.c_id

where c.c_id="01" order by sc.s_Score desc) c1 ,

(select @i:=0) a

union all

select c2.s_id,c2.c_id,c2.c_name,c2.s_Score,@ii:=@ii+1 from (select c.c_name,sc.* from Course c

left join Score sc on sc.c_id=c.c_id

where c.c_id="02" order by sc.s_Score desc) c2 ,

(select @ii:=0) aa

union all

select c3.s_id,c3.c_id,c3.c_name,c3.s_Score,@iii:=@iii+1 from (select c.c_name,sc.* from Course c

left join Score sc on sc.c_id=c.c_id

where c.c_id="03" order by sc.s_Score desc) c3;

set @iii=0;

select a.*

from (select st.s_id, st.s_name, c.c_name, s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '01' and s2.s_Score >= s.s_Score and s2.c_id='01'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

union all

select b.*

from (select st.s_id, st.s_name, c.c_name, s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '02' and s2.s_Score >= s.s_Score and s2.c_id='02'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) b

union all

select c.*

from (select st.s_id, st.s_name, c.c_name, s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '03' and s2.s_Score >= s.s_Score and s2.c_id='03'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) c;

+------+--------+--------+---------+------+

| s_id | s_name | c_name | s_Score | 排名 |

+------+--------+--------+---------+------+

| 01 | 赵雷 | 语文 | 80 | 1 |

| 03 | 孙风 | 语文 | 80 | 1 |

| 05 | 周梅 | 语文 | 76 | 2 |

| 02 | 钱电 | 语文 | 70 | 3 |

| 04 | 李云 | 语文 | 50 | 4 |

| 06 | 吴兰 | 语文 | 31 | 5 |

| 01 | 赵雷 | 数学 | 90 | 1 |

| 07 | 郑竹 | 数学 | 89 | 2 |

| 05 | 周梅 | 数学 | 87 | 3 |

| 03 | 孙风 | 数学 | 80 | 4 |

| 02 | 钱电 | 数学 | 60 | 5 |

| 04 | 李云 | 数学 | 30 | 6 |

| 01 | 赵雷 | 英语 | 99 | 1 |

| 07 | 郑竹 | 英语 | 98 | 2 |

| 02 | 钱电 | 英语 | 80 | 3 |

| 03 | 孙风 | 英语 | 80 | 3 |

| 06 | 吴兰 | 英语 | 34 | 4 |

| 04 | 李云 | 英语 | 20 | 5 |

+------+--------+--------+---------+------+

# 20、查询学生的总成绩并进行排名

select st.s_id,st.s_name

,(case when sum(sc.s_Score) is null then 0 else sum(sc.s_Score) end)

from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id order by sum(sc.s_Score) desc;

select st.s_id, st.s_name, (case when sum(s.s_Score) is null then 0 else sum(s.s_Score) end) '总成绩'

from Student st left outer join Score s on st.s_id = s.s_id

group by st.s_id, st.s_name

order by sum(s.s_Score) desc;

+------+--------+--------+

| s_id | s_name | 总成绩 |

+------+--------+--------+

| 01 | 赵雷 | 269 |

| 03 | 孙风 | 240 |

| 02 | 钱电 | 210 |

| 07 | 郑竹 | 187 |

| 05 | 周梅 | 163 |

| 04 | 李云 | 100 |

| 06 | 吴兰 | 65 |

| 08 | 王菊 | 0 |

+------+--------+--------+

# 21、查询不同老师所教不同课程平均分从高到低显示

select t.t_id, t.t_name, c.c_name, avg(s.s_Score) '平均分'

from Teacher t left outer join Course c on t.t_id = c.t_id

left outer join Score s on c.c_id = s.c_id

group by t.t_id, t.t_name, c.c_name

order by avg(s.s_Score) desc;

+------+--------+--------+---------+

| t_id | t_name | c_name | 平均分 |

+------+--------+--------+---------+

| 01 | 张三 | 数学 | 72.6667 |

| 03 | 王五 | 英语 | 68.5000 |

| 02 | 李四 | 语文 | 64.5000 |

+------+--------+--------+---------+

# 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

select st.*, c.c_name, s.s_Score

from Student st

left join Score s on st.s_id = s.s_id

left join Course c on s.c_id = c.c_id

where s.c_id = '01' and (

s.s_Score between

(select distinct a.s_Score

from (select s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '01' and s2.s_Score >= s.s_Score and s2.c_id='01'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

where a.排名 = 3)

and

(select distinct a.s_Score

from (select s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '01' and s2.s_Score >= s.s_Score and s2.c_id='01'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

where a.排名 = 2)

)

union all

select st.*, c.c_name, s.s_Score

from Student st

left join Score s on st.s_id = s.s_id

left join Course c on s.c_id = c.c_id

where s.c_id = '02' and (

s.s_Score between

(select distinct a.s_Score

from (select s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '02' and s2.s_Score >= s.s_Score and s2.c_id='02'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

where a.排名 = 3)

and

(select distinct a.s_Score

from (select s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '02' and s2.s_Score >= s.s_Score and s2.c_id='02'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

where a.排名 = 2)

)

union all

select st.*, c.c_name, s.s_Score

from Student st

left join Score s on st.s_id = s.s_id

left join Course c on s.c_id = c.c_id

where s.c_id = '03' and (

s.s_Score between

(select distinct a.s_Score

from (select s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '03' and s2.s_Score >= s.s_Score and s2.c_id='03'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

where a.排名 = 3)

and

(select distinct a.s_Score

from (select s.s_Score, count(distinct s2.s_Score) '排名'

from Score s inner join Student st on s.s_id = st.s_id

inner join Course c on s.c_id = c.c_id, Score s2

where c.c_id = '03' and s2.s_Score >= s.s_Score and s2.c_id='03'

group by st.s_id, st.s_name, c.c_name, s.s_Score

order by s.s_Score desc) a

where a.排名 = 2)

);

+------+--------+------------+-------+--------+---------+

| s_id | s_name | s_birth | s_sex | c_name | s_Score |

+------+--------+------------+-------+--------+---------+

| 02 | 钱电 | 1990-12-21 | 男 | 语文 | 70 |

| 05 | 周梅 | 1991-12-01 | 女 | 语文 | 76 |

| 05 | 周梅 | 1991-12-01 | 女 | 数学 | 87 |

| 07 | 郑竹 | 1989-07-01 | 女 | 数学 | 89 |

| 02 | 钱电 | 1990-12-21 | 男 | 英语 | 80 |

| 03 | 孙风 | 1990-05-20 | 男 | 英语 | 80 |

| 07 | 郑竹 | 1989-07-01 | 女 | 英语 | 98 |

+------+--------+------------+-------+--------+---------+

# *23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[60-0]及所占百分比

select c.c_id,c.c_name

,((select count(1) from Score sc where sc.c_id=c.c_id and sc.s_Score<=100 and sc.s_Score>80)/(select count(1) from Score sc where sc.c_id=c.c_id )) "100-85"

,((select count(1) from Score sc where sc.c_id=c.c_id and sc.s_Score<=85 and sc.s_Score>70)/(select count(1) from Score sc where sc.c_id=c.c_id )) "85-70"

,((select count(1) from Score sc where sc.c_id=c.c_id and sc.s_Score<=70 and sc.s_Score>60)/(select count(1) from Score sc where sc.c_id=c.c_id )) "70-60"

,((select count(1) from Score sc where sc.c_id=c.c_id and sc.s_Score<=60 and sc.s_Score>=0)/(select count(1) from Score sc where sc.c_id=c.c_id )) "60-0"

from Course c order by c.c_id;

+------+--------+--------+--------+--------+--------+

| c_id | c_name | 100-85 | 85-70 | 70-60 | 60-0 |

+------+--------+--------+--------+--------+--------+

| 01 | 语文 | 0.0000 | 0.5000 | 0.1667 | 0.3333 |

| 02 | 数学 | 0.5000 | 0.1667 | 0.0000 | 0.3333 |

| 03 | 英语 | 0.3333 | 0.3333 | 0.0000 | 0.3333 |

+------+--------+--------+--------+--------+--------+

--count(1) 会统计表中的所有的记录数,包含字段为null 的记录。

--count(字段) 会统计该字段在表中出现的次数,忽略字段为null 的情况。即不统计字段为null 的记录。

# 24、查询学生平均成绩及其名次

select a.*, count(distinct b.平均成绩) '名次'

from

(select st.s_id, st.s_name, (case when avg(s.s_Score) is null then 0 else avg(s.s_Score) end) '平均成绩'

from Student st left join Score s on st.s_id=s.s_id

group by st.s_id, st.s_name) a,

(select st.s_id, (case when avg(s.s_Score) is null then 0 else avg(s.s_Score) end) '平均成绩'

from Student st left join Score s on st.s_id=s.s_id

group by st.s_id) b

where a.平均成绩<=b.平均成绩

group by a.s_id

order by a.平均成绩 desc;

+------+--------+----------+------+

| s_id | s_name | 平均成绩 | 名次 |

+------+--------+----------+------+

| 07 | 郑竹 | 93.5000 | 1 |

| 01 | 赵雷 | 89.6667 | 2 |

| 05 | 周梅 | 81.5000 | 3 |

| 03 | 孙风 | 80.0000 | 4 |

| 02 | 钱电 | 70.0000 | 5 |

| 04 | 李云 | 33.3333 | 6 |

| 06 | 吴兰 | 32.5000 | 7 |

| 08 | 王菊 | 0.0000 | 8 |

+------+--------+----------+------+

# 25、查询各科成绩前三名的记录

select a.*

from (

select st.*, c.c_name, s.s_Score

from Student st

left join Score s on st.s_id=s.s_id

left join Course c on c.c_id=s.c_id

where c.c_id='01' and s.s_Score between (

select distinct a1.s_Score

from (

select a2.s_id, a2.s_Score, count(distinct a3.s_Score) '名次'

from Score a2, Score a3

where a2.c_id='01' and a3.c_id='01' and a2.s_Score<=a3.s_Score

group by a2.s_id, a2.s_Score

) a1

where a1.名次=3)

and

(select max(s_Score) from Score where c_id='01')

) a

union all

select b.*

from (

select st.*, c.c_name, s.s_Score

from Student st

left join Score s on st.s_id=s.s_id

left join Course c on c.c_id=s.c_id

where c.c_id='02' and s.s_Score between (

select distinct a1.s_Score

from (

select a2.s_id, a2.s_Score, count(distinct a3.s_Score) '名次'

from Score a2, Score a3

where a2.c_id='02' and a3.c_id='02' and a2.s_Score<=a3.s_Score

group by a2.s_id, a2.s_Score

) a1

where a1.名次=3)

and

(select max(s_Score) from Score where c_id='02')

) b

union all

select c.*

from (

select st.*, c.c_name, s.s_Score

from Student st

left join Score s on st.s_id=s.s_id

left join Course c on c.c_id=s.c_id

where c.c_id='03' and s.s_Score between (

select distinct a1.s_Score

from (

select a2.s_id, a2.s_Score, count(distinct a3.s_Score) '名次'

from Score a2, Score a3

where a2.c_id='03' and a3.c_id='03' and a2.s_Score<=a3.s_Score

group by a2.s_id, a2.s_Score

) a1

where a1.名次=3)

and

(select max(s_Score) from Score where c_id='03')

) c;

+------+--------+------------+-------+--------+---------+

| s_id | s_name | s_birth | s_sex | c_name | s_Score |

+------+--------+------------+-------+--------+---------+

| 01 | 赵雷 | 1990-01-01 | 男 | 语文 | 80 |

| 02 | 钱电 | 1990-12-21 | 男 | 语文 | 70 |

| 03 | 孙风 | 1990-05-20 | 男 | 语文 | 80 |

| 05 | 周梅 | 1991-12-01 | 女 | 语文 | 76 |

| 01 | 赵雷 | 1990-01-01 | 男 | 数学 | 90 |

| 05 | 周梅 | 1991-12-01 | 女 | 数学 | 87 |

| 07 | 郑竹 | 1989-07-01 | 女 | 数学 | 89 |

| 01 | 赵雷 | 1990-01-01 | 男 | 英语 | 99 |

| 02 | 钱电 | 1990-12-21 | 男 | 英语 | 80 |

| 03 | 孙风 | 1990-05-20 | 男 | 英语 | 80 |

| 07 | 郑竹 | 1989-07-01 | 女 | 英语 | 98 |

+------+--------+------------+-------+--------+---------+

# 26、查询每门课程被选修的学生数

select c.c_id,c.c_name,count(1) from Course c

left join Score sc on sc.c_id=c.c_id

inner join Student st on st.s_id=c.c_id

group by st.s_id;

select c.c_id, c.c_name, count(s.s_id) '选修人数'

from Course c

left join Score s on c.c_id=s.c_id

group by c.c_id, c.c_name;

+------+--------+----------+

| c_id | c_name | 选修人数 |

+------+--------+----------+

| 01 | 语文 | 6 |

| 02 | 数学 | 6 |

| 03 | 英语 | 6 |

+------+--------+----------+

# 27、查询出只有两门课程的全部学生的学号和姓名

select st.s_id,st.s_name from Student st

left join Score sc on sc.s_id=st.s_id

inner join Course c on c.c_id=sc.c_id

group by st.s_id having count(1)=2;

select st.s_id, st.s_name

from Student st

left join Score s on st.s_id=s.s_id

group by st.s_id, st.s_name

having count(s.c_id)=2;

+------+--------+

| s_id | s_name |

+------+--------+

| 05 | 周梅 |

| 06 | 吴兰 |

| 07 | 郑竹 |

+------+--------+

# 28、查询男生、女生人数

select st.s_sex,count(1) from Student st group by st.s_sex;

+-------+----------+

| s_sex | count(1) |

+-------+----------+

| 男 | 4 |

| 女 | 4 |

+-------+----------+

# 29、查询名字中含有"风"字的学生信息

select st.* from Student st where st.s_name like "%风%";

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 03 | 孙风 | 1990-05-20 | 男 |

+------+--------+------------+-------+

# 30、查询同名同性学生名单,并统计同名人数

select st.*,count(1) from Student st group by st.s_name,st.s_sex having count(1)>1;

Empty set (0.00 sec)

注意5.7 以后的版本要修改配置文件:

如果my.cnf中有sql_mode配置,则将ONLY_FULL_GROUP_BY去掉。

如果没有,则将下面内容放到相应位置

[mysqld]

sql_mode=STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_AUTO_CREATE_USER,NO_ENGINE_SUBSTITUTION

发现从 MySQL 5.7.5 开始,默认 SQL 模式包括 ONLY_FULL_GROUP_BY。

(在 5.7.5 之前,MySQL 不检测函数依赖,并且默认不启用 ONLY_FULL_GROUP_BY。)

# 31、查询1990年出生的学生名单

select st.* from Student st where st.s_birth like "1990%";

select * from Student where year(s_birth) = '1990';

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

| 08 | 王菊 | 1990-01-20 | 女 |

+------+--------+------------+-------+

# 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

select c.c_id,c.c_name,avg(sc.s_Score) from Course c

inner join Score sc on sc.c_id=c.c_id

group by c.c_id, c.c_name order by avg(sc.s_Score) desc,c.c_id asc;

+------+--------+-----------------+

| c_id | c_name | avg(sc.s_Score) |

+------+--------+-----------------+

| 02 | 数学 | 72.6667 |

| 03 | 英语 | 68.5000 |

| 01 | 语文 | 64.5000 |

+------+--------+-----------------+

# 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

select st.s_id,st.s_name,avg(sc.s_Score) from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id having avg(sc.s_Score)>=85;

+------+--------+-----------------+

| s_id | s_name | avg(sc.s_Score) |

+------+--------+-----------------+

| 01 | 赵雷 | 89.6667 |

| 07 | 郑竹 | 93.5000 |

+------+--------+-----------------+

# 34、查询课程名称为"数学",且分数低于60的学生姓名和分数

select st.s_name,sc.s_Score from Student st

inner join Score sc on sc.s_id=st.s_id and sc.s_Score<60

inner join Course c on c.c_id=sc.c_id and c.c_name ="数学" ;

select st.s_name, s.s_Score

from Student st

left join Score s on st.s_id=s.s_id

left join Course c on c.c_id=s.c_id

where c.c_name='数学' and s.s_Score<60;

+--------+---------+

| s_name | s_Score |

+--------+---------+

| 李云 | 30 |

+--------+---------+

# 35、查询所有学生的课程及分数情况;

select st.s_id,st.s_name,c.c_name,sc.s_Score from Student st

left join Score sc on sc.s_id=st.s_id

left join Course c on c.c_id =sc.c_id

order by st.s_id,c.c_name;

+------+--------+--------+---------+

| s_id | s_name | c_name | s_Score |

+------+--------+--------+---------+

| 01 | 赵雷 | 数学 | 90 |

| 01 | 赵雷 | 英语 | 99 |

| 01 | 赵雷 | 语文 | 80 |

| 02 | 钱电 | 数学 | 60 |

| 02 | 钱电 | 英语 | 80 |

| 02 | 钱电 | 语文 | 70 |

| 03 | 孙风 | 数学 | 80 |

| 03 | 孙风 | 英语 | 80 |

| 03 | 孙风 | 语文 | 80 |

| 04 | 李云 | 数学 | 30 |

| 04 | 李云 | 英语 | 20 |

| 04 | 李云 | 语文 | 50 |

| 05 | 周梅 | 数学 | 87 |

| 05 | 周梅 | 语文 | 76 |

| 06 | 吴兰 | 英语 | 34 |

| 06 | 吴兰 | 语文 | 31 |

| 07 | 郑竹 | 数学 | 89 |

| 07 | 郑竹 | 英语 | 98 |

| 08 | 王菊 | NULL | NULL |

+------+--------+--------+---------+

# 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数

select st2.s_id,st2.s_name,c2.c_name,sc2.s_Score from Student st2

left join Score sc2 on sc2.s_id=st2.s_id

left join Course c2 on c2.c_id=sc2.c_id

where st2.s_id in(

select st.s_id from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id having min(sc.s_Score)>70)

order by s_id;

+------+--------+--------+---------+

| s_id | s_name | c_name | s_Score |

+------+--------+--------+---------+

| 01 | 赵雷 | 语文 | 80 |

| 01 | 赵雷 | 数学 | 90 |

| 01 | 赵雷 | 英语 | 99 |

| 03 | 孙风 | 语文 | 80 |

| 03 | 孙风 | 数学 | 80 |

| 03 | 孙风 | 英语 | 80 |

| 05 | 周梅 | 语文 | 76 |

| 05 | 周梅 | 数学 | 87 |

| 07 | 郑竹 | 数学 | 89 |

| 07 | 郑竹 | 英语 | 98 |

+------+--------+--------+---------+

# 37、查询不及格的课程

select st.s_id,c.c_name,st.s_name,sc.s_Score from Student st

inner join Score sc on sc.s_id=st.s_id and sc.s_Score<60

inner join Course c on c.c_id=sc.c_id ;

select st.s_id, st.s_name, c.c_name, s.s_Score from Student st

left join Score s on s.s_id=st.s_id

left join Course c on c.c_id=s.c_id

where s.s_Score<60;

+------+--------+--------+---------+

| s_id | c_name | s_name | s_Score |

+------+--------+--------+---------+

| 04 | 语文 | 李云 | 50 |

| 04 | 数学 | 李云 | 30 |

| 04 | 英语 | 李云 | 20 |

| 06 | 语文 | 吴兰 | 31 |

| 06 | 英语 | 吴兰 | 34 |

+------+--------+--------+---------+

# 38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名

select st.s_id,st.s_name,sc.s_Score from Student st

inner join Score sc on sc.s_id=st.s_id and sc.c_id="01" and sc.s_Score>=80;

+------+--------+---------+

| s_id | s_name | s_Score |

+------+--------+---------+

| 01 | 赵雷 | 80 |

| 03 | 孙风 | 80 |

+------+--------+---------+

# 39、求每门课程的学生人数

select c.c_id,c.c_name,count(1) from Course c

inner join Score sc on sc.c_id=c.c_id

group by c.c_id;

select c.c_id, c.c_name, count(st.s_id)

from Course c

left join Score s on c.c_id=s.c_id

left join Student st on s.s_id=st.s_id

group by c.c_id, c.c_name;

+------+--------+----------------+

| c_id | c_name | count(st.s_id) |

+------+--------+----------------+

| 01 | 语文 | 6 |

| 02 | 数学 | 6 |

| 03 | 英语 | 6 |

+------+--------+----------------+

# 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩

select st.*,c.c_name,sc.s_Score,t.t_name from Student st

inner join Score sc on sc.s_id=st.s_id

inner join Course c on c.c_id=sc.c_id

inner join Teacher t on t.t_id=c.t_id and t.t_name="张三"

order by sc.s_Score desc

limit 0,1;

select st.*, s.s_Score, t.t_name, c.c_name

from Student st

left join Score s on st.s_id=s.s_id

left join Course c on s.c_id=c.c_id

left join Teacher t on c.t_id=t.t_id

where t.t_name='张三'

and s.s_Score = (

select distinct max(s2.s_Score)

from Score s2 left join Course c2 on s2.c_id=c2.c_id

left join Teacher t2 on c2.t_id=t2.t_id

where t2.t_name='张三'

);

+------+--------+------------+-------+---------+--------+--------+

| s_id | s_name | s_birth | s_sex | s_Score | t_name | c_name |

+------+--------+------------+-------+---------+--------+--------+

| 01 | 赵雷 | 1990-01-01 | 男 | 90 | 张三 | 数学 |

+------+--------+------------+-------+---------+--------+--------+

# *41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

select st.s_id,st.s_name,sc.c_id,sc.s_Score,c.c_name from Student st

left join Score sc on sc.s_id=st.s_id

left join Course c on c.c_id=sc.c_id

where (

select count(1) from Student st2

left join Score sc2 on sc2.s_id=st2.s_id

left join Course c2 on c2.c_id=sc2.c_id

where sc.s_Score=sc2.s_Score and c.c_id!=c2.c_id

)>1;

+------+--------+------+---------+--------+

| s_id | s_name | c_id | s_Score | c_name |

+------+--------+------+---------+--------+

| 01 | 赵雷 | 01 | 80 | 语文 |

| 03 | 孙风 | 01 | 80 | 语文 |

| 03 | 孙风 | 02 | 80 | 数学 |

| 02 | 钱电 | 03 | 80 | 英语 |

| 03 | 孙风 | 03 | 80 | 英语 |

+------+--------+------+---------+--------+

5 rows in set (0.00 sec)

# 42、查询每门功成绩最好的前两名

select a.* from (select st.s_id,st.s_name,c.c_name,sc.s_Score from Student st

left join Score sc on sc.s_id=st.s_id

inner join Course c on c.c_id=sc.c_id and c.c_id="01"

order by sc.s_Score desc limit 0,2) a

union all

select b.* from (select st.s_id,st.s_name,c.c_name,sc.s_Score from Student st

left join Score sc on sc.s_id=st.s_id

inner join Course c on c.c_id=sc.c_id and c.c_id="02"

order by sc.s_Score desc limit 0,2) b

union all

select c.* from (select st.s_id,st.s_name,c.c_name,sc.s_Score from Student st

left join Score sc on sc.s_id=st.s_id

inner join Course c on c.c_id=sc.c_id and c.c_id="03"

order by sc.s_Score desc limit 0,2) c;

+------+--------+--------+---------+

| s_id | s_name | c_name | s_Score |

+------+--------+--------+---------+

| 01 | 赵雷 | 语文 | 80 |

| 03 | 孙风 | 语文 | 80 |

| 01 | 赵雷 | 数学 | 90 |

| 07 | 郑竹 | 数学 | 89 |

| 01 | 赵雷 | 英语 | 99 |

| 07 | 郑竹 | 英语 | 98 |

+------+--------+--------+---------+

-- 借鉴(更准确,漂亮):

select a.s_id,a.c_id,a.s_Score from Score a

where (select COUNT(1) from Score b where b.c_id=a.c_id and b.s_Score>=a.s_Score)<=2 order by a.c_id;

# 43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列

select sc.c_id,count(1) from Score sc

left join Course c on c.c_id=sc.c_id

group by c.c_id having count(1)>5

order by count(1) desc,sc.c_id asc;

select c.c_id, count(s.s_id)

from Course c left join Score s on c.c_id=s.c_id

group by c.c_id

having count(s.s_id)>5

order by count(s.s_id) desc, c.c_id;

+------+---------------+

| c_id | count(s.s_id) |

+------+---------------+

| 01 | 6 |

| 02 | 6 |

| 03 | 6 |

+------+---------------+

# 44、检索至少选修两门课程的学生学号

select st.s_id from Student st

left join Score sc on sc.s_id=st.s_id

group by st.s_id having count(1)>=2;

+------+

| s_id |

+------+

| 01 |

| 02 |

| 03 |

| 04 |

| 05 |

| 06 |

| 07 |

+------+

# 45、查询选修了全部课程的学生信息

select st.*

from Student st left join Score s on st.s_id=s.s_id

group by st.s_id

having count(s.c_id)=(select count(*) from Course);

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 02 | 钱电 | 1990-12-21 | 男 |

| 03 | 孙风 | 1990-05-20 | 男 |

| 04 | 李云 | 1990-08-06 | 男 |

+------+--------+------------+-------+

# *46、查询各学生的年龄(实岁)

select st.*,timestampdiff(year,st.s_birth,now()) from Student st;

+------+--------+------------+-------+--------------------------------------+

| s_id | s_name | s_birth | s_sex | timestampdiff(year,st.s_birth,now()) |

+------+--------+------------+-------+--------------------------------------+

| 01 | 赵雷 | 1990-01-01 | 男 | 33 |

| 02 | 钱电 | 1990-12-21 | 男 | 32 |

| 03 | 孙风 | 1990-05-20 | 男 | 33 |

| 04 | 李云 | 1990-08-06 | 男 | 33 |

| 05 | 周梅 | 1991-12-01 | 女 | 32 |

| 06 | 吴兰 | 1992-03-01 | 女 | 31 |

| 07 | 郑竹 | 1989-07-01 | 女 | 34 |

| 08 | 王菊 | 1990-01-20 | 女 | 33 |

+------+--------+------------+-------+--------------------------------------+

8 rows in set (0.01 sec)

# 47、查询本周过生日的学生

select st.* from Student st

where week(now())=week(date_format(st.s_birth,'%Y%m%d'));

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 02 | 钱电 | 1990-12-21 | 男 |

+------+--------+------------+-------+

1 row in set (0.01 sec)

# 48、查询下周过生日的学生(还要排除闰年情况)

select st.* from Student st

where week(now())+1=week(date_format(st.s_birth,'%Y%m%d'));

Empty set (0.00 sec)

# 49、查询本月过生日的学生

select st.* from Student st

where month(now())=month(date_format(st.s_birth,'%Y%m%d'));

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 02 | 钱电 | 1990-12-21 | 男 |

| 05 | 周梅 | 1991-12-01 | 女 |

+------+--------+------------+-------+

2 rows in set (0.01 sec)

# *50、查询下月过生日的学生

# 注意:当 当前月为12时,用month(now())+1为13而不是1,可用timestampadd()函数或mod取模

select st.* from Student st

where month(timestampadd(month,1,now()))=month(date_format(st.s_birth,'%Y%m%d'));

-- 或

select st.* from Student st where (month(now()) + 1) mod 12 = month(date_format(st.s_birth,'%Y%m%d'))

+------+--------+------------+-------+

| s_id | s_name | s_birth | s_sex |

+------+--------+------------+-------+

| 01 | 赵雷 | 1990-01-01 | 男 |

| 08 | 王菊 | 1990-01-20 | 女 |

+------+--------+------------+-------+

2 rows in set (0.00 sec)

二、综合演练:

Sakila 是一个在线 DVD 出租商店数据库,

为各种 MySQL 文档、书籍、教程、文章、示例等提供了一个标准数据库模式;同时,

它还可以用于演示 MySQL 的其他功能特性,例如视图、存储过程和触发器。

Sakila 数据库的模式结构如下图所示:

Sakila 数据库提供了以下数据表:

actor, 演员信息表。通过 film_actor 表和 film 表进行关联。

film, 电影信息表。film 引用了 language 表,同时被 film_category、film_actor 以及 inventory 表引用。

film_actor, 电影演员表。film 表和 actor 表之间的多对多关系。

film_category, 电影分类表。film 表和 category 表之间的多对多关系。

category, 分类表。通过 film_category 表和 film 表进行关联。

inventory, 电影库存表。每部电影在不同商店里的库存,被 rental 表引用。

film_text, 电影描述表。包含了film表中的 film_id、title 以及description三个字段,通过film表触发器进行数据同步。

language, 语言信息表。language 表被 film 表引用。

address, 地址信息表。其中主键字段 address_id 是 customer、staff 以及 store 表上的外键引用字段,

同时引用了 city 表。

city, 城市信息表。引用了 country 表,同时被 address 表引用。

country, 国家信息表。country 表被 city 表引用。

customer, 客户信息表。引用了 address 和 store 表,同时被 payment 和 rental 表引用。

payment, 付款信息表。引用了 customer、staff 以及 rental 表。

rental, 租赁信息表,每个 DVD 每次被租赁的信息。引用了 inventory、customer 以及 staff 表,

同时被 payment 表引用。

staff, 员工信息表。引用了 store 和 address 表,同时被 rental、payment 以及 store 表引用。

store, 商店信息表,引用了 staff 和 address 表,同时被 staff、customer 以及 inventory 表引用。

Sakila 数据库提供了以下视图:

actor_info, 包含了所有的演员,以及他们演出过的电影。

customer_list, 客户和地址信息列表。

film_list, 电影信息和参与的演员。

nicer_but_slower_film_list, 电影信息和参与的演员,演员的姓名调整为首字母大写。

sales_by_film_category, 按照不同电影分类统计的销售金额,同一个电影可能被分为多个类别。

sales_by_store,按照商店统计的销售金额。

staff_list, 员工列表,包括地址和所属的商店。

Sakila 数据库提供了以下存储过程和函数:

film_in_stock, 存储过程,获取指定电影在指定商店内未出租的 DVD。

film_not_in_stock, 存储过程,获取指定电影在指定商店内已出租未归还的 DVD。

rewards_report, 存储过程,获取上个月的最佳客户列表。

get_customer_balance, 存储函数,返回指定客户在某个日期之前的欠款。

inventory_held_by_customer,存储函数,返回正在租赁某个 DVD 的客户。

inventory_in_stock, 存储函数,返回某个 DVD 是否可出租。TRUE 表示可以出租,FALSE 表示已出租未归还。

Sakila 数据库包含了以下触发器:

customer_create_date, 插入数据时将 customer 表的 create_date 字段设置为当前日期和时间。

payment_date, 插入数据时将 payment 表的 payment_date 字段设置为当前日期和时间。

rental_date, 插入数据时将 rental 表的 rental_date 字段设置为当前日期和时间。

ins_film, 将 film 表上插入的相关数据复制一份到 film_text 表。

upd_film, 将 film 表上更新的相关数据同步到 film_text 表。

del_film, 删除 film 表数据时同步删除 film_text 表上的相关数据。

Sakila 数据库的创建脚本可以点此下载,然后运行以下命令创建数据库并初始化数据:

shell> mysql -t < sakila-schema.sql;

shell> mysql -t < sakila-data.sql;

创建成功之后,可以执行以下语句进行验证:

mysql> USE sakila;

Database changed

mysql> SHOW FULL TABLES;

+----------------------------+------------+

| Tables_in_sakila | Table_type |

+----------------------------+------------+

| actor | BASE TABLE |

| actor_info | VIEW |

| address | BASE TABLE |

| category | BASE TABLE |

| city | BASE TABLE |

| country | BASE TABLE |

| customer | BASE TABLE |

| customer_list | VIEW |

| film | BASE TABLE |

| film_actor | BASE TABLE |

| film_category | BASE TABLE |

| film_list | VIEW |

| film_text | BASE TABLE |

| inventory | BASE TABLE |

| language | BASE TABLE |

| nicer_but_slower_film_list | VIEW |

| payment | BASE TABLE |

| rental | BASE TABLE |

| sales_by_film_category | VIEW |

| sales_by_store | VIEW |

| staff | BASE TABLE |

| staff_list | VIEW |

| store | BASE TABLE |

+----------------------------+------------+

23 rows in set (0.01 sec)

mysql> SELECT COUNT(*) FROM film;

+----------+

| COUNT(*) |

+----------+

| 1000 |

+----------+

1 row in set (0.00 sec)

mysql> SELECT COUNT(*) FROM film_text;

+----------+

| COUNT(*) |

+----------+

| 1000 |

+----------+

1 row in set (0.00 sec)

关于 Sakila 数据库的详细介绍和使用可以查看官方文档。https://dev.mysql.com/doc/sakila/en/

以上资料来源:https://www.cnblogs.com/dersome/p/14902838.html

文章来源:https://blog.csdn.net/m2282475145/article/details/135314108
本文来自互联网用户投稿,该文观点仅代表作者本人,不代表本站立场。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。