MySQL作业（4）数据表综合练习

发布时间：2024年01月19日

数据表综合练习

题目：
1.查询" 01 "课程比" 02 "课程成绩高的学生的信息及课程分数
- 1.1查询同时存在" 01 "课程和" 02 "课程的情况
- 1.2查询存在" 01 "课程但可能不存在" 02 "课程的情况(不存在时显示为 null )
- 1.3查询不存在" 01 "课程但存在" 02 "课程的情况
2.查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩
3.查询在 SC 表存在成绩的学生信息
4.查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null )
- 4.1 查有成绩的学生信息
5.查询「李」姓老师的数量
6.查询学过「张三」老师授课的同学的信息
7.查询没有学全所有课程的同学的信息
8.查询至少有一门课与学号为" 01 "的同学所学相同的同学的信
9.查询和" 01 "号的同学学习的课程完全相同的其他同学的信息
10.查询没学过"张三"老师讲授的任一门课程的学生姓名
11.查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩
12.检索" 01 "课程分数小于 60，按分数降序排列的学生信息
13.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
14.查询各科成绩最高分、最低分和平均分：
15.按各科成绩进行排序，并显示排名， Score 重复时保留名次空缺
- 15.1 按各科成绩进行排序，并显示排名， Score 重复时合并名次
16.查询学生的总成绩，并进行排名，总分重复时保留名次空缺
- 16.1 查询学生的总成绩，并进行排名，总分重复时不保留名次空缺
17.统计各科成绩各分数段人数：课程编号，课程名称，[100-85]，[85-70]，[70-60]，[60-0] 及所占百分比
18.查询各科成绩前三名的记录
19.查询每门课程被选修的学生数
20.查询出只选修两门课程的学生学号和姓名
21.查询男生、女生人数
22.查询名字中含有「风」字的学生信息
23.查询同名同性学生名单，并统计同名人数
24.查询 1990 年出生的学生名单
25.查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列
26.查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩
27.查询课程名称为「数学」，且分数低于 60 的学生姓名和分数
28.查询所有学生的课程及分数情况（存在学生没成绩，没选课的情况）
29.查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数
30.查询不及格的课程
31.查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名
32.求每门课程的学生人数
33.成绩不重复，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩
34.成绩有重复的情况下，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩
35.查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
36.查询每门功成绩最好的前两名
37.统计每门课程的学生选修人数（超过 5 人的课程才统计）。
38.检索至少选修两门课程的学生学号
39.查询选修了全部课程的学生信息
40.查询各学生的年龄，只按年份来算
41.按照出生日期来算，当前月日 < 出生年月的月日则，年龄减一
42.查询本周过生日的学生
43.查询下周过生日的学生
44.查询本月过生日的学生
45.查询下月过生日的学生

题目：

数据表介绍

–1.学生表
Student(SId,Sname,Sage,Ssex)
–SId 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别

–2.课程表
Course(CId,Cname,TId)
–CId 课程编号,Cname 课程名称,TId 教师编号

–3.教师表
Teacher(TId,Tname)
–TId 教师编号,Tname 教师姓名

–4.成绩表
SC(SId,CId,score)
–SId 学生编号,CId 课程编号,score 分数

学生表 Student
create table Student(SId varchar(10),Sname varchar(10),Sage datetime,Ssex varchar(10));
insert into Student values(‘01’ , ‘赵雷’ , ‘1990-01-01’ , ‘男’);
insert into Student values(‘02’ , ‘钱电’ , ‘1990-12-21’ , ‘男’);
insert into Student values(‘03’ , ‘孙风’ , ‘1990-12-20’ , ‘男’);
insert into Student values(‘04’ , ‘李云’ , ‘1990-12-06’ , ‘男’);
insert into Student values(‘05’ , ‘周梅’ , ‘1991-12-01’ , ‘女’);
insert into Student values(‘06’ , ‘吴兰’ , ‘1992-01-01’ , ‘女’);
insert into Student values(‘07’ , ‘郑竹’ , ‘1989-01-01’ , ‘女’);
insert into Student values(‘09’ , ‘张三’ , ‘2017-12-20’ , ‘女’);
insert into Student values(‘10’ , ‘李四’ , ‘2017-12-25’ , ‘女’);
insert into Student values(‘11’ , ‘李四’ , ‘2012-06-06’ , ‘女’);
insert into Student values(‘12’ , ‘赵六’ , ‘2013-06-13’ , ‘女’);
insert into Student values(‘13’ , ‘孙七’ , ‘2014-06-01’ , ‘女’);

mysql> create table Student(SId varchar(10),Sname varchar(10),Sage datetime,Ssex varchar(10));
Query OK, 0 rows affected (0.03 sec)

mysql> insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Student values('02' , '钱电' , '1990-12-21' , '男');
Query OK, 1 row affected (0.00 sec)
mysql> insert into Student values('03' , '孙风' , '1990-12-20' , '男');
Query OK, 1 row affected (0.00 sec)
mysql> insert into Student values('04' , '李云' , '1990-12-06' , '男');
Query OK, 1 row affected (0.00 sec)
mysql> insert into Student values('05' , '周梅' , '1991-12-01' , '女');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Student values('06' , '吴兰' , '1992-01-01' , '女');
Query OK, 1 row affected (0.00 sec
mysql> insert into Student values('07' , '郑竹' , '1989-01-01' , '女');
Query OK, 1 row affected (0.00 sec)
mysql> insert into Student values('09' , '张三' , '2017-12-20' , '女');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Student values('10' , '李四' , '2017-12-25' , '女');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Student values('11' , '李四' , '2012-06-06' , '女');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Student values('12' , '赵六' , '2013-06-13' , '女');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Student values('13' , '孙七' , '2014-06-01' , '女');
Query OK, 1 row affected (0.01 sec)

mysql> select * from Student;
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 03   | 孙风  | 1990-12-20 00:00:00 | 男   |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |
| 05   | 周梅  | 1991-12-01 00:00:00 | 女   |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
| 09   | 张三  | 2017-12-20 00:00:00 | 女   |
| 10   | 李四  | 2017-12-25 00:00:00 | 女   |
| 11   | 李四  | 2012-06-06 00:00:00 | 女   |
| 12   | 赵六  | 2013-06-13 00:00:00 | 女   |
| 13   | 孙七  | 2014-06-01 00:00:00 | 女   |
+------+-------+---------------------+------+
12 rows in set (0.00 sec)

mysql>

科目表 Course
create table Course(CId varchar(10),Cname nvarchar(10),TId varchar(10));
insert into Course values(‘01’ , ‘语文’ , ‘02’);
insert into Course values(‘02’ , ‘数学’ , ‘01’);
insert into Course values(‘03’ , ‘英语’ , ‘03’);

mysql> create table Course(CId varchar(10),Cname nvarchar(10),TId varchar(10));
Query OK, 0 rows affected, 1 warning (0.02 sec)

mysql> insert into Course values('01' , '语文' , '02');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Course values('02' , '数学' , '01');
Query OK, 1 row affected (0.01 sec)
mysql> insert into Course values('03' , '英语' , '03');
Query OK, 1 row affected (0.00 sec)

mysql> select * from Course;
+------+-------+------+
| CId  | Cname | TId  |
+------+-------+------+
| 01   | 语文  | 02   |
| 02   | 数学  | 01   |
| 03   | 英语  | 03   |
+------+-------+------+
3 rows in set (0.00 sec)

mysql>

教师表 Teacher
create table Teacher(TId varchar(10),Tname varchar(10));
insert into Teacher values(‘01’ , ‘张三’);
insert into Teacher values(‘02’ , ‘李四’);
insert into Teacher values(‘03’ , ‘王五’);

mysql> create table Teacher(TId varchar(10),Tname varchar(10));
Query OK, 0 rows affected (0.02 sec)

mysql> insert into Teacher values('01' , '张三');
Query OK, 1 row affected (0.00 sec)
mysql> insert into Teacher values('02' , '李四');
Query OK, 1 row affected (0.00 sec)
mysql> insert into Teacher values('03' , '王五');
Query OK, 1 row affected (0.01 sec)

mysql> select * from Teacher;
+------+-------+
| TId  | Tname |
+------+-------+
| 01   | 张三  |
| 02   | 李四  |
| 03   | 王五  |
+------+-------+
3 rows in set (0.00 sec)

mysql>

成绩表 SC
create table SC(SId varchar(10),CId varchar(10),score decimal(18,1));
insert into SC values(‘01’ , ‘01’ , 80);
insert into SC values(‘01’ , ‘02’ , 90);
insert into SC values(‘01’ , ‘03’ , 99);
insert into SC values(‘02’ , ‘01’ , 70);
insert into SC values(‘02’ , ‘02’ , 60);
insert into SC values(‘02’ , ‘03’ , 80);
insert into SC values(‘03’ , ‘01’ , 80);
insert into SC values(‘03’ , ‘02’ , 80);
insert into SC values(‘03’ , ‘03’ , 80);
insert into SC values(‘04’ , ‘01’ , 50);
insert into SC values(‘04’ , ‘02’ , 30);
insert into SC values(‘04’ , ‘03’ , 20);
insert into SC values(‘05’ , ‘01’ , 76);
insert into SC values(‘05’ , ‘02’ , 87);
insert into SC values(‘06’ , ‘01’ , 31);
insert into SC values(‘06’ , ‘03’ , 34);
insert into SC values(‘07’ , ‘02’ , 89);
insert into SC values(‘07’ , ‘03’ , 98);

mysql> create table SC(SId varchar(10),CId varchar(10),score decimal(18,1));
Query OK, 0 rows affected (0.02 sec)

mysql> insert into SC values('01' , '01' , 80);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('01' , '02' , 90);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('01' , '03' , 99);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('02' , '01' , 70);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('02' , '02' , 60);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('02' , '03' , 80);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('03' , '01' , 80);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('03' , '02' , 80);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('03' , '03' , 80);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('04' , '01' , 50);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('04' , '02' , 30);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('04' , '03' , 20);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('05' , '01' , 76);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('05' , '02' , 87);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('06' , '01' , 31);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('06' , '03' , 34);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('07' , '02' , 89);
Query OK, 1 row affected (0.00 sec)
mysql> insert into SC values('07' , '03' , 98);
Query OK, 1 row affected (0.01 sec)

mysql> select * from SC;
+------+------+-------+
| SId  | CId  | score |
+------+------+-------+
| 01   | 01   |  80.0 |
| 01   | 02   |  90.0 |
| 01   | 03   |  99.0 |
| 02   | 01   |  70.0 |
| 02   | 02   |  60.0 |
| 02   | 03   |  80.0 |
| 03   | 01   |  80.0 |
| 03   | 02   |  80.0 |
| 03   | 03   |  80.0 |
| 04   | 01   |  50.0 |
| 04   | 02   |  30.0 |
| 04   | 03   |  20.0 |
| 05   | 01   |  76.0 |
| 05   | 02   |  87.0 |
| 06   | 01   |  31.0 |
| 06   | 03   |  34.0 |
| 07   | 02   |  89.0 |
| 07   | 03   |  98.0 |
+------+------+-------+
18 rows in set (0.00 sec)

mysql>

1.查询" 01 “课程比” 02 "课程成绩高的学生的信息及课程分数

mysql> select * from Student RIGHT JOIN (
    ->     select t1.SId, class1, class2 from
    ->           (select SId, score as class1 from sc where sc.CId = '01')as t1,
    ->           (select SId, score as class2 from sc where sc.CId = '02')as t2
    ->     where t1.SId = t2.SId AND t1.class1 > t2.class2
    -> )r
    -> on Student.SId = r.SId;
+------+-------+---------------------+------+------+--------+--------+
| SId  | Sname | Sage                | Ssex | SId  | class1 | class2 |
+------+-------+---------------------+------+------+--------+--------+
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   | 02   |   70.0 |   60.0 |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   | 04   |   50.0 |   30.0 |
+------+-------+---------------------+------+------+--------+--------+
2 rows in set (0.01 sec)

mysql> select * from  (
    ->     select t1.SId, class1, class2
    ->     from
    ->         (SELECT SId, score as class1 FROM sc WHERE sc.CId = '01') AS t1,
    ->         (SELECT SId, score as class2 FROM sc WHERE sc.CId = '02') AS t2
    ->     where t1.SId = t2.SId and t1.class1 > t2.class2
    -> ) r
    -> LEFT JOIN Student
    -> ON Student.SId = r.SId;
+------+--------+--------+------+-------+---------------------+------+
| SId  | class1 | class2 | SId  | Sname | Sage                | Ssex |
+------+--------+--------+------+-------+---------------------+------+
| 02   |   70.0 |   60.0 | 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 04   |   50.0 |   30.0 | 04   | 李云  | 1990-12-06 00:00:00 | 男   |
+------+--------+--------+------+-------+---------------------+------+
2 rows in set (0.00 sec)

mysql>

1.1查询同时存在" 01 “课程和” 02 "课程的情况

mysql> select * from
    ->     (select * from sc where sc.CId = '01') as t1,
    ->     (select * from sc where sc.CId = '02') as t2
    -> where t1.SId = t2.SId;
+------+------+-------+------+------+-------+
| SId  | CId  | score | SId  | CId  | score |
+------+------+-------+------+------+-------+
| 01   | 01   |  80.0 | 01   | 02   |  90.0 |
| 02   | 01   |  70.0 | 02   | 02   |  60.0 |
| 03   | 01   |  80.0 | 03   | 02   |  80.0 |
| 04   | 01   |  50.0 | 04   | 02   |  30.0 |
| 05   | 01   |  76.0 | 05   | 02   |  87.0 |
+------+------+-------+------+------+-------+
5 rows in set (0.00 sec)

mysql>

1.2查询存在" 01 “课程但可能不存在” 02 "课程的情况(不存在时显示为 null )

mysql> select * from
    -> (select * from sc where sc.CId = '02') as t2
    -> right join
    -> (select * from sc where sc.CId = '01') as t1
    -> on t1.SId = t2.SId;
+------+------+-------+------+------+-------+
| SId  | CId  | score | SId  | CId  | score |
+------+------+-------+------+------+-------+
| 01   | 02   |  90.0 | 01   | 01   |  80.0 |
| 02   | 02   |  60.0 | 02   | 01   |  70.0 |
| 03   | 02   |  80.0 | 03   | 01   |  80.0 |
| 04   | 02   |  30.0 | 04   | 01   |  50.0 |
| 05   | 02   |  87.0 | 05   | 01   |  76.0 |
| NULL | NULL |  NULL | 06   | 01   |  31.0 |
+------+------+-------+------+------+-------+
6 rows in set (0.00 sec)

mysql>

1.3查询不存在" 01 “课程但存在” 02 "课程的情况

mysql> select * from sc
    -> where sc.SId not in (
    ->     select SId from sc
    ->     where sc.CId = '01'
    -> )
    -> AND sc.CId= '02';
+------+------+-------+
| SId  | CId  | score |
+------+------+-------+
| 07   | 02   |  89.0 |
+------+------+-------+
1 row in set (0.00 sec)

mysql>

2.查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩

mysql> select student.SId,sname,ss from student,(
    ->     select SId, AVG(score) as ss from sc
    ->     GROUP BY SId
    ->     HAVING AVG(score)> 60
    ->     )r
    -> where student.sid = r.sid;
+------+-------+----------+
| SId  | sname | ss       |
+------+-------+----------+
| 01   | 赵雷  | 89.66667 |
| 02   | 钱电  | 70.00000 |
| 03   | 孙风  | 80.00000 |
| 05   | 周梅  | 81.50000 |
| 07   | 郑竹  | 93.50000 |
+------+-------+----------+
5 rows in set (0.00 sec)

mysql> select Student.SId, Student.Sname, r.ss from Student right join(
    ->       select SId, AVG(score) AS ss from sc
    ->       GROUP BY SId
    ->       HAVING AVG(score)> 60
    -> )r on Student.SId = r.SId;
+------+-------+----------+
| SId  | Sname | ss       |
+------+-------+----------+
| 01   | 赵雷  | 89.66667 |
| 02   | 钱电  | 70.00000 |
| 03   | 孙风  | 80.00000 |
| 05   | 周梅  | 81.50000 |
| 07   | 郑竹  | 93.50000 |
+------+-------+----------+
5 rows in set (0.00 sec)

mysql> select s.SId,ss,Sname from(
    -> select SId, AVG(score) as ss from sc
    -> GROUP BY SId
    -> HAVING AVG(score)> 60
    -> )r left join
    -> (select Student.SId, Student.Sname from
    -> Student)s on s.SId = r.SId;
+------+----------+-------+
| SId  | ss       | Sname |
+------+----------+-------+
| 01   | 89.66667 | 赵雷  |
| 02   | 70.00000 | 钱电  |
| 03   | 80.00000 | 孙风  |
| 05   | 81.50000 | 周梅  |
| 07   | 93.50000 | 郑竹  |
+------+----------+-------+
5 rows in set (0.00 sec)

mysql>

3.查询在 SC 表存在成绩的学生信息

4.查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null )

mysql> select s.sid, s.sname,r.coursenumber,r.scoresum
    -> from (
    ->     (select student.sid,student.sname
    ->     from student
    ->     )s
    ->     left join
    ->     (select
    ->         sc.sid, sum(sc.score) as scoresum, count(sc.cid) as coursenumber
    ->         from sc
    ->         group by sc.sid
    ->     )r
    ->    on s.sid = r.sid
    -> );
+------+-------+--------------+----------+
| sid  | sname | coursenumber | scoresum |
+------+-------+--------------+----------+
| 01   | 赵雷  |            3 |    269.0 |
| 02   | 钱电  |            3 |    210.0 |
| 03   | 孙风  |            3 |    240.0 |
| 04   | 李云  |            3 |    100.0 |
| 05   | 周梅  |            2 |    163.0 |
| 06   | 吴兰  |            2 |     65.0 |
| 07   | 郑竹  |            2 |    187.0 |
| 09   | 张三  |         NULL |     NULL |
| 10   | 李四  |         NULL |     NULL |
| 11   | 李四  |         NULL |     NULL |
| 12   | 赵六  |         NULL |     NULL |
| 13   | 孙七  |         NULL |     NULL |
+------+-------+--------------+----------+
12 rows in set (0.00 sec)

mysql>

4.1 查有成绩的学生信息

mysql> select * from student
    -> where exists (select sc.sid from sc where student.sid = sc.sid);
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 03   | 孙风  | 1990-12-20 00:00:00 | 男   |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |
| 05   | 周梅  | 1991-12-01 00:00:00 | 女   |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
+------+-------+---------------------+------+
7 rows in set (0.00 sec)

mysql> select * from student
    -> where student.sid in (select sc.sid from sc);
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 03   | 孙风  | 1990-12-20 00:00:00 | 男   |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |
| 05   | 周梅  | 1991-12-01 00:00:00 | 女   |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
+------+-------+---------------------+------+
7 rows in set (0.00 sec)

mysql>

5.查询「李」姓老师的数量

mysql> select count(*)
    -> from teacher
    -> where tname like '李%';
+----------+
| count(*) |
+----------+
|        1 |
+----------+
1 row in set (0.00 sec)

mysql>

6.查询学过「张三」老师授课的同学的信息

mysql> select student.* from student,teacher,course,sc
    -> where
    ->     student.sid = sc.sid
    ->     and course.cid=sc.cid
    ->     and course.tid = teacher.tid
    ->     and tname = '张三';
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 03   | 孙风  | 1990-12-20 00:00:00 | 男   |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |
| 05   | 周梅  | 1991-12-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
+------+-------+---------------------+------+
6 rows in set (0.00 sec)

mysql>

7.查询没有学全所有课程的同学的信息

mysql> select * from student
    -> where student.sid not in (
    ->   select sc.sid from sc
    ->   group by sc.sid
    ->   having count(sc.cid)= (select count(cid) from course)
    -> );
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 05   | 周梅  | 1991-12-01 00:00:00 | 女   |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
| 09   | 张三  | 2017-12-20 00:00:00 | 女   |
| 10   | 李四  | 2017-12-25 00:00:00 | 女   |
| 11   | 李四  | 2012-06-06 00:00:00 | 女   |
| 12   | 赵六  | 2013-06-13 00:00:00 | 女   |
| 13   | 孙七  | 2014-06-01 00:00:00 | 女   |
+------+-------+---------------------+------+
8 rows in set (0.00 sec)

mysql>

8.查询至少有一门课与学号为" 01 "的同学所学相同的同学的信

mysql> select * from student
    -> where student.sid in (
    ->     select sc.sid from sc
    ->     where sc.cid in(
    ->         select sc.cid from sc
    ->         where sc.sid = '01'
    ->     )
    -> );
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 03   | 孙风  | 1990-12-20 00:00:00 | 男   |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |
| 05   | 周梅  | 1991-12-01 00:00:00 | 女   |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
+------+-------+---------------------+------+
7 rows in set (0.00 sec)

mysql>

9.查询和" 01 "号的同学学习的课程完全相同的其他同学的信息

10.查询没学过"张三"老师讲授的任一门课程的学生姓名

mysql> select * from student
    ->     where student.sid not in(
    ->         select sc.sid from sc where sc.cid in(
    ->             select course.cid from course where course.tid in(
    ->                 select teacher.tid from teacher where tname = "张三"
    ->             )
    ->         )
    ->     );
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 09   | 张三  | 2017-12-20 00:00:00 | 女   |
| 10   | 李四  | 2017-12-25 00:00:00 | 女   |
| 11   | 李四  | 2012-06-06 00:00:00 | 女   |
| 12   | 赵六  | 2013-06-13 00:00:00 | 女   |
| 13   | 孙七  | 2014-06-01 00:00:00 | 女   |
+------+-------+---------------------+------+
6 rows in set (0.00 sec)

mysql> select * from student
    -> where student.sid not in(
    ->     select sc.sid from sc,course,teacher
    ->     where
    ->         sc.cid = course.cid
    ->         and course.tid = teacher.tid
    ->         and teacher.tname= "张三"
    -> );
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 09   | 张三  | 2017-12-20 00:00:00 | 女   |
| 10   | 李四  | 2017-12-25 00:00:00 | 女   |
| 11   | 李四  | 2012-06-06 00:00:00 | 女   |
| 12   | 赵六  | 2013-06-13 00:00:00 | 女   |
| 13   | 孙七  | 2014-06-01 00:00:00 | 女   |
+------+-------+---------------------+------+
6 rows in set (0.00 sec)

mysql>

11.查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩

mysql> select student.SId, student.Sname,b.avg
    -> from student RIGHT JOIN
    -> (select sid, AVG(score) as avg from sc
    ->     where sid in (
    ->               select sid from sc
    ->               where score<60
    ->               GROUP BY sid
    ->               HAVING count(score)>1)
    ->     GROUP BY sid) b on student.sid=b.sid;
+------+-------+----------+
| SId  | Sname | avg      |
+------+-------+----------+
| 04   | 李云  | 33.33333 |
| 06   | 吴兰  | 32.50000 |
+------+-------+----------+
2 rows in set (0.00 sec)

mysql>

12.检索" 01 "课程分数小于 60，按分数降序排列的学生信息

mysql> select student.*, sc.score from student, sc
    -> where student.sid = sc.sid
    -> and sc.score < 60
    -> and cid = "01"
    -> ORDER BY sc.score DESC;
+------+-------+---------------------+------+-------+
| SId  | Sname | Sage                | Ssex | score |
+------+-------+---------------------+------+-------+
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |  50.0 |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |  31.0 |
+------+-------+---------------------+------+-------+
2 rows in set (0.00 sec)

mysql>

13.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

mysql> select *  from sc
    -> left join (
    ->     select sid,avg(score) as avscore from sc
    ->     group by sid
    ->     )r
    -> on sc.sid = r.sid
    -> order by avscore desc;
+------+------+-------+------+----------+
| SId  | CId  | score | sid  | avscore  |
+------+------+-------+------+----------+
| 07   | 02   |  89.0 | 07   | 93.50000 |
| 07   | 03   |  98.0 | 07   | 93.50000 |
| 01   | 01   |  80.0 | 01   | 89.66667 |
| 01   | 02   |  90.0 | 01   | 89.66667 |
| 01   | 03   |  99.0 | 01   | 89.66667 |
| 05   | 01   |  76.0 | 05   | 81.50000 |
| 05   | 02   |  87.0 | 05   | 81.50000 |
| 03   | 01   |  80.0 | 03   | 80.00000 |
| 03   | 02   |  80.0 | 03   | 80.00000 |
| 03   | 03   |  80.0 | 03   | 80.00000 |
| 02   | 01   |  70.0 | 02   | 70.00000 |
| 02   | 02   |  60.0 | 02   | 70.00000 |
| 02   | 03   |  80.0 | 02   | 70.00000 |
| 04   | 01   |  50.0 | 04   | 33.33333 |
| 04   | 02   |  30.0 | 04   | 33.33333 |
| 04   | 03   |  20.0 | 04   | 33.33333 |
| 06   | 01   |  31.0 | 06   | 32.50000 |
| 06   | 03   |  34.0 | 06   | 32.50000 |
+------+------+-------+------+----------+
18 rows in set (0.00 sec)

mysql>

14.查询各科成绩最高分、最低分和平均分：

以如下形式显示：课程 ID，课程 name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率
及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90
要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列

15.按各科成绩进行排序，并显示排名， Score 重复时保留名次空缺

15.1 按各科成绩进行排序，并显示排名， Score 重复时合并名次

16.查询学生的总成绩，并进行排名，总分重复时保留名次空缺

16.1 查询学生的总成绩，并进行排名，总分重复时不保留名次空缺

17.统计各科成绩各分数段人数：课程编号，课程名称，[100-85]，[85-70]，[70-60]，[60-0] 及所占百分比

18.查询各科成绩前三名的记录

mysql> select * from sc
    -> where (
    -> select count(*) from sc as a
    -> where sc.cid = a.cid and sc.score<a.score
    -> )< 3
    -> order by cid asc, sc.score desc;
+------+------+-------+
| SId  | CId  | score |
+------+------+-------+
| 01   | 01   |  80.0 |
| 03   | 01   |  80.0 |
| 05   | 01   |  76.0 |
| 01   | 02   |  90.0 |
| 07   | 02   |  89.0 |
| 05   | 02   |  87.0 |
| 01   | 03   |  99.0 |
| 07   | 03   |  98.0 |
| 02   | 03   |  80.0 |
| 03   | 03   |  80.0 |
+------+------+-------+
10 rows in set (0.00 sec)

mysql>

19.查询每门课程被选修的学生数

mysql> select cid, count(sid) from sc
    -> group by cid;
+------+------------+
| cid  | count(sid) |
+------+------------+
| 01   |          6 |
| 02   |          6 |
| 03   |          6 |
+------+------------+
3 rows in set (0.00 sec)

mysql>

20.查询出只选修两门课程的学生学号和姓名

嵌套查询
mysql> select student.sid, student.sname from student
    -> where student.sid in
    -> (select sc.sid from sc
    -> group by sc.sid
    -> having count(sc.cid)=2
    -> );
+------+-------+
| sid  | sname |
+------+-------+
| 05   | 周梅  |
| 06   | 吴兰  |
| 07   | 郑竹  |
+------+-------+
3 rows in set (0.00 sec)

21.查询男生、女生人数

mysql> select ssex, count(*) from student
    -> group by ssex;
+------+----------+
| ssex | count(*) |
+------+----------+
| 男   |        4 |
| 女   |        8 |
+------+----------+
2 rows in set (0.00 sec)

mysql>

22.查询名字中含有「风」字的学生信息

23.查询同名同性学生名单，并统计同名人数

mysql> select sname, count(*) from student
    -> group by sname
    -> having count(*)>1;
+-------+----------+
| sname | count(*) |
+-------+----------+
| 李四  |        2 |
+-------+----------+
1 row in set (0.00 sec)

mysql> select * from student
    -> where sname in (
    -> select sname from student
    -> group by sname
    -> having count(*)>1
    -> );
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 10   | 李四  | 2017-12-25 00:00:00 | 女   |
| 11   | 李四  | 2012-06-06 00:00:00 | 女   |
+------+-------+---------------------+------+
2 rows in set (0.00 sec)

mysql>

24.查询 1990 年出生的学生名单

mysql> select *
    -> from student
    -> where YEAR(student.Sage)=1990;
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 02   | 钱电  | 1990-12-21 00:00:00 | 男   |
| 03   | 孙风  | 1990-12-20 00:00:00 | 男   |
| 04   | 李云  | 1990-12-06 00:00:00 | 男   |
+------+-------+---------------------+------+
4 rows in set (0.00 sec)

mysql>

25.查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列

26.查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩

27.查询课程名称为「数学」，且分数低于 60 的学生姓名和分数

mysql> select student.sname, sc.score from student, sc, course
    -> where student.sid = sc.sid
    -> and course.cid = sc.cid
    -> and course.cname = "数学"
    -> and sc.score < 60;
+-------+-------+
| sname | score |
+-------+-------+
| 李云  |  30.0 |
+-------+-------+
1 row in set (0.00 sec)

mysql>

28.查询所有学生的课程及分数情况（存在学生没成绩，没选课的情况）

mysql> select student.sname, cid, score from student
    -> left join sc
    -> on student.sid = sc.sid;
+-------+------+-------+
| sname | cid  | score |
+-------+------+-------+
| 赵雷  | 03   |  99.0 |
| 赵雷  | 02   |  90.0 |
| 赵雷  | 01   |  80.0 |
| 钱电  | 03   |  80.0 |
| 钱电  | 02   |  60.0 |
| 钱电  | 01   |  70.0 |
| 孙风  | 03   |  80.0 |
| 孙风  | 02   |  80.0 |
| 孙风  | 01   |  80.0 |
| 李云  | 03   |  20.0 |
| 李云  | 02   |  30.0 |
| 李云  | 01   |  50.0 |
| 周梅  | 02   |  87.0 |
| 周梅  | 01   |  76.0 |
| 吴兰  | 03   |  34.0 |
| 吴兰  | 01   |  31.0 |
| 郑竹  | 03   |  98.0 |
| 郑竹  | 02   |  89.0 |
| 张三  | NULL |  NULL |
| 李四  | NULL |  NULL |
| 李四  | NULL |  NULL |
| 赵六  | NULL |  NULL |
| 孙七  | NULL |  NULL |
+-------+------+-------+
23 rows in set (0.00 sec)

mysql>

29.查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数

mysql> select student.sname, course.cname,sc.score from student,course,sc
    -> where sc.score>70
    -> and student.sid = sc.sid
    -> and sc.cid = course.cid;
+-------+-------+-------+
| sname | cname | score |
+-------+-------+-------+
| 赵雷  | 英语  |  99.0 |
| 赵雷  | 数学  |  90.0 |
| 赵雷  | 语文  |  80.0 |
| 钱电  | 英语  |  80.0 |
| 孙风  | 英语  |  80.0 |
| 孙风  | 数学  |  80.0 |
| 孙风  | 语文  |  80.0 |
| 周梅  | 数学  |  87.0 |
| 周梅  | 语文  |  76.0 |
| 郑竹  | 英语  |  98.0 |
| 郑竹  | 数学  |  89.0 |
+-------+-------+-------+
11 rows in set (0.00 sec)

mysql>

30.查询不及格的课程

mysql> select cid from sc
    -> where score< 60
    -> group by cid;
+------+
| cid  |
+------+
| 01   |
| 02   |
| 03   |
+------+
3 rows in set (0.00 sec)

mysql> select DISTINCT sc.CId
    -> from sc
    -> where sc.score <60;
+------+
| CId  |
+------+
| 01   |
| 02   |
| 03   |
+------+
3 rows in set (0.00 sec)

mysql>

31.查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名

mysql> select student.sid,student.sname
    -> from student,sc
    -> where cid="01"
    -> and score>=80
    -> and student.sid = sc.sid;
+------+-------+
| sid  | sname |
+------+-------+
| 01   | 赵雷  |
| 03   | 孙风  |
+------+-------+
2 rows in set (0.00 sec)

mysql>

32.求每门课程的学生人数

mysql> select sc.CId,count(*) as 学生人数
    -> from sc
    -> GROUP BY sc.CId;
+------+----------+
| CId  | 学生人数 |
+------+----------+
| 01   |        6 |
| 02   |        6 |
| 03   |        6 |
+------+----------+
3 rows in set (0.00 sec)

mysql>

33.成绩不重复，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩

34.成绩有重复的情况下，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩

mysql> select student.*, sc.score, sc.cid from student, teacher, course,sc
    -> where teacher.tid = course.tid
    -> and sc.sid = student.sid
    -> and sc.cid = course.cid
    -> and teacher.tname = "张三"
    -> and sc.score = (
    ->     select Max(sc.score)
    ->     from sc,student, teacher, course
    ->     where teacher.tid = course.tid
    ->     and sc.sid = student.sid
    ->     and sc.cid = course.cid
    ->     and teacher.tname = "张三"
    -> );
+------+-------+---------------------+------+-------+------+
| SId  | Sname | Sage                | Ssex | score | cid  |
+------+-------+---------------------+------+-------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |  90.0 | 02   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |  90.0 | 02   |
+------+-------+---------------------+------+-------+------+
2 rows in set (0.00 sec)

mysql>

35.查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

36.查询每门功成绩最好的前两名

37.统计每门课程的学生选修人数（超过 5 人的课程才统计）。

mysql> select sc.cid, count(sid) as cc from sc
    -> group by cid
    -> having cc >5;
+------+----+
| cid  | cc |
+------+----+
| 01   |  6 |
| 02   |  6 |
| 03   |  6 |
+------+----+
3 rows in set (0.00 sec)

mysql>

38.检索至少选修两门课程的学生学号

mysql> select sid, count(cid) as cc from sc
    -> group by sid
    -> having cc>=2;
+------+----+
| sid  | cc |
+------+----+
| 01   |  3 |
| 02   |  3 |
| 03   |  3 |
| 04   |  3 |
| 05   |  2 |
| 06   |  2 |
| 07   |  2 |
+------+----+
7 rows in set (0.00 sec)

mysql>

39.查询选修了全部课程的学生信息

40.查询各学生的年龄，只按年份来算

41.按照出生日期来算，当前月日 < 出生年月的月日则，年龄减一

42.查询本周过生日的学生

43.查询下周过生日的学生

44.查询本月过生日的学生

mysql> select *
    -> from student
    -> where MONTH(student.Sage)=MONTH(CURDATE());
+------+-------+---------------------+------+
| SId  | Sname | Sage                | Ssex |
+------+-------+---------------------+------+
| 01   | 赵雷  | 1990-01-01 00:00:00 | 男   |
| 06   | 吴兰  | 1992-01-01 00:00:00 | 女   |
| 07   | 郑竹  | 1989-01-01 00:00:00 | 女   |
+------+-------+---------------------+------+
3 rows in set (0.00 sec)

45.查询下月过生日的学生

文章来源:https://blog.csdn.net/weixin_64183819/article/details/135692230
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