【LeetCode】每日一题 2023_12_27 保龄球游戏的获胜者（模拟）

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简单题时间

题目：保龄球游戏的获胜者

题目链接：2660. 保龄球游戏的获胜者

题目描述

代码与解题思路

func isWinner(player1 []int, player2 []int) (ans int) {
    sum1, sum2 := 0, 0
    for i := 0; i < len(player1); i++ {
        if i >= 2 {
            if player1[i-2] == 10 || player1[i-1] == 10 {
                sum1 += player1[i]*2
            } else {
                sum1 += player1[i]
            }
            if player2[i-2] == 10 || player2[i-1] == 10 {
                sum2 += player2[i]*2
            } else {
                sum2 += player2[i]
            }
        } else if i == 1 {
            if player1[i-1] == 10 {
                sum1 += player1[i]*2
            } else {
                sum1 += player1[i]
            }
            if player2[i-1] == 10 {
                sum2 += player2[i]*2
            } else {
                sum2 += player2[i]
            }
        } else {
            sum1 += player1[i]
            sum2 += player2[i]
        }
    }
    if sum1 > sum2 {
        ans = 1
    } else if sum1 < sum2 {
        ans = 2
    }
    return ans
}

我有罪，我写了一坨屎山，这种求两个一模一样逻辑的题目，下次一定抽象出一个函数然后分别调用

欣赏一下官方题解

func isWinner(player1 []int, player2 []int) int {
    s1, s2 := score(player1), score(player2)
    if s1 == s2 {
        return 0
    } else if s1 > s2 {
        return 1
    } else {
        return 2
    }
}

func score(player []int) int {
    res := 0
    for i, x := range player {
        if i > 0 && player[i - 1] == 10 || i > 1 && player[i - 2] == 10 {
            res += 2 * x
        } else {
            res += x
        }
    }
    return res
}