C#高级 07XML操作

1 XML文件

• Xml文件是一种可扩展标记语言，在.NET中xml文件常用来描述数据和存储数据。是处理当前结构化信息的有利工具
• Xml文件存储和描述数据的方式主要有以下几种

方式一 ：通过标签的属性进行描述和存储

<?xml version="1.0" encoding="utf-8" ?>
<SkillInfo>
  <SkillList>
    <Skill
      SkillID="20002"
      SkillEngName="Smash"
      TriggerType ="1"
      ImageFile="data/gfx/image/gui_icon_skill_000.dds"
      AvailableRace="7">
    </Skill>
  </SkillList>
</SkillInfo>

方式二 ：通过标签之间的值进行描述和存储

<?xml version="1.0" encoding="utf-8" ?>
<skills>
  <skill>
    <id>2</id>
    <name >法倫</name>
    <damage>288</damage>
  </skill>
  </skills>

2.上两种方式获取数据的方式也有所不同，下面具体展开：

• 方式一 读取XML文件方法

XmlFileDto.cs

public class XmlFileDto
{
    public string SkillID { get; set; }
    public string SkillEngName { get; set; }
    public string TriggerType { get; set; }
    public string ImageFile { get; set; }
    public string AvailableRace { get; set; }
}

public class ReadXmlFileCode
{
    public void ReadXmlFileTools()
    {
    	//在上面给出XmlFileDto
        List<XmlFileDto> list = new List<XmlFileDto>();
        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.Load("XMLFile.xml");

        //读取根节点
        XmlNode root = xmlDoc.ChildNodes[1];
        //保存根节点下的元素集合
        XmlNode skillNodeList = root.ChildNodes[0];
        XmlNodeList nodeList = skillNodeList.ChildNodes;
        foreach (XmlNode node in nodeList)
        {
            XmlFileDto xmlObj = new XmlFileDto();

            //获取属性值
            XmlAttributeCollection attrCol = node.Attributes;

            XmlAttribute attrSkillID = attrCol["SkillID"];
            xmlObj.SkillID = attrSkillID.Value;

            XmlAttribute attrSkillEngName = attrCol["SkillEngName"];
            xmlObj.SkillEngName = attrSkillEngName.Value;

            XmlAttribute attrTriggerType = attrCol["TriggerType"];
            xmlObj.TriggerType = attrTriggerType.Value;

            XmlAttribute attrImageFile = attrCol["ImageFile"];
            xmlObj.ImageFile = attrImageFile.Value;

            XmlAttribute AvailableRace = attrCol["AvailableRace"];
            xmlObj.AvailableRace = AvailableRace.Value;

            //获取Name元素值
            XmlNode nameNode = node.ChildNodes[0];
            //XmlNode eleName = nameNode["name"];
            xmlObj.Name = nameNode.InnerText;

            list.Add(xmlObj);
        }
        foreach (XmlFileDto s in list)
        {
            Console.WriteLine(s.SkillID + " : " + s.SkillEngName + " : " + s.TriggerType + " : " + s.ImageFile + " : " + s.AvailableRace + " : " + s.Name);
        }
    }
}

• 方式二 读取XML文件的方法

class Skill
{
    public int ID { get; set; }
    public  string Name { get; set; }
    public int Damage { get; set; }  
}

internal class Program
{
    static void Main(string[] args)
    {
    	//Skill.cs在上面给出
        List<Skill> list = new List<Skill>();
		//专门解析XML文档的工具类
		XmlDocument xmlDocument = new XmlDocument();
		//传入路径
		xmlDocument.Load("Skills.xml");
		//FirstChild会把<?xml version="1.0" encoding="utf-8" ?>当做第一个节点，如果ChildNodes[0]会使后面ChildNodes获取值为空
		XmlNode root = xmlDocument.ChildNodes[1];
		//保存根节点下的节点集合
		XmlNodeList skillList = root.ChildNodes;
		foreach (XmlNode skill in skillList) 
		{
		    Skill skillObj = new Skill();
			XmlElement idEle = skill["id"];
			skillObj.ID = Int32.Parse(idEle.InnerText);
			
			XmlElement nameEle = skill["name"];
			skillObj.Name = nameEle.InnerText;
		
			XmlElement damageEle = skill["damage"];
			skillObj.Damage = Int32.Parse(idEle.InnerText);
			
			list.Add(skillObj);
		}
		foreach (Skill s in list)
		{
		    Console.WriteLine(s.ID+" : "+s.Name+" : "+ s.Damage);
		}
    }
    
}