力扣每日一题
题目:2415. 反转二叉树的奇数层
日期:2023-12-15
用时:6 m 51 s
时间:0 ms
内存:46.97 MB
代码:
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public TreeNode reverseOddLevels(TreeNode root) {
dfs(root.left, root.right, 1);
return root;
}
void dfs(TreeNode left,TreeNode right,int odd){
if(left==null){
return;
}
if(odd==1){
int temp = left.val;
left.val = right.val;
right.val = temp;
}
dfs(left.left, right.right, 1-odd);
dfs(left.right, right.left, 1-odd);
}
}