虽然力扣对我来说很难,但只要每天刷一点,就会慢慢增强能力,总有一天刷动力扣的难题,所以说,今天也是刷力扣的一天。?😆😆
/**
?* Note: The returned array must be malloced, assume caller calls free().
?*/
int* getConcatenation(int* nums, int numsSize, int* returnSize) {
? ? int* p = (int*)malloc(numsSize * 2 * sizeof(int));
? ? *returnSize = numsSize * 2;
? ? for (int i = 0; i < numsSize; i++)
? ? {
? ? ? ? p[i] = nums[i];
? ? ? ? p[i + numsSize] = nums[i];
? ? }
? ? ? ? return p;
}