「HDLBits题解」Shift Registers

发布时间:2024年01月22日

本专栏的目的是分享可以通过HDLBits仿真的Verilog代码 以提供参考 各位可同时参考我的代码和官方题解代码 或许会有所收益


题目链接:Shift4 - HDLBits

module top_module(
    input clk,
    input areset,  // async active-high reset to zero
    input load,
    input ena,
    input [3:0] data,
    output reg [3:0] q); 

    always @ (posedge clk or posedge areset) begin 
        if (areset) q <= 0 ;
        else if (load) q <= data ; 
        else if (ena) q <= {1'b0, q[3:1]} ;
        else q <= q ; 
    end
    
endmodule

题目链接:Rotate100 - HDLBits

module top_module(
    input clk,
    input load,
    input [1:0] ena,
    input [99:0] data,
    output reg [99:0] q); 
    
    always @ (posedge clk) begin
        if (load) q <= data ; 
        else 
            if (ena == 1) q <= {q[0], q[99:1]};
        else if (ena == 2) q <= {q[98:0], q[99]};
            else q <= q ; 
    end

endmodule

题目链接:Shift18 - HDLBits

module top_module(
    input clk,
    input load,
    input ena,
    input [1:0] amount,
    input [63:0] data,
    output reg [63:0] q); 
    
    always @ (posedge clk) begin 
        if (load) q <= data ; 
        else 
            if (ena) begin 
                case (amount) 
                    0 : q <= {q[62:0], 1'b0} ;
                    1 : q <= {q[55:0], 8'b0} ; 
                    2 : q <= {q[63], q[63:1]} ;
                    3 : q <= {q[63], {7{q[63]}}, q[63:8]} ;
                endcase
            end
        else q <= q ; 
    end

endmodule

题目链接:Lfsr5 - HDLBits

module top_module(
    input clk,
    input reset,    // Active-high synchronous reset to 5'h1
    output [4:0] q
); 
    reg q4, q3, q2, q1, q0 ; 
    
    assign q = {q4, q3, q2, q1, q0} ;
    
    always @ (posedge clk) begin 
        if (reset) q4 <= 0 ; 
        else q4 <= 0 ^ q0 ; 
    end
    
    always @ (posedge clk) begin 
        if (reset) q3 <= 0 ; 
        else q3 <= q4 ; 
    end
    
    always @ (posedge clk) begin 
        if (reset) q2 <= 0 ; 
        else q2 <= q3 ^ q0 ; 
    end
    
    always @ (posedge clk) begin 
        if (reset) q1 <= 0 ; 
        else q1 <= q2 ; 
    end
    
    always @ (posedge clk) begin 
        if (reset) q0 <= 1 ; 
        else q0 <= q1 ; 
    end
    

endmodule

题目链接:Mt2015 lfsr - HDLBits

module top_module (
	input [2:0] SW,      // R
	input [1:0] KEY,     // L and clk
	output [2:0] LEDR);  // Q
    
    reg q0, q1, q2 ; 
    reg o0, o1, o2 ; 
    wire L, clk ; 
    wire t ;
    
    assign L = KEY[1] ; 
    assign clk = KEY[0] ; 
    assign LEDR = {q2, q1, q0} ;
    assign t = q1 ^ q2 ;
    
    always @ (*) begin 
        if (L) o0 <= SW[0] ; 
        else o0 <= q2 ; 
    end
    
    always @ (*) begin 
        if (L) o1 <= SW[1] ; 
        else o1 <= q0 ; 
    end
    
    always @ (*) begin 
        if (L) o2 <= SW[2] ; 
        else o2 <= t ; 
    end
	
    always @ (posedge clk) begin 
        q0 <= o0 ; 
        q1 <= o1 ; 
        q2 <= o2 ; 
    end

endmodule

题目链接:Lfsr32 - HDLBits

module top_module(
    input clk,
    input reset,    // Active-high synchronous reset to 32'h1
    output [31:0] q
); 
    reg [31:0] q_next;
    
    always @(*) begin
        q_next = q[31:1];	// Shift all the bits. This is incorrect for q_next[4] and q_next[2]
        q_next[31] = q[0];	// Give q_next[4] and q_next[2] their correct assignments
        q_next[21] = q[22] ^ q[0];
        q_next[1] = q[2] ^ q[0];
        q_next[0] = q[1] ^ q[0];
	end
    
    always @(posedge clk) begin
		if (reset)
			q <= 32'h1;
		else
			q <= q_next;
	end

endmodule

题目链接:Exams/m2014 q4k - HDLBits

module top_module (
    input clk,
    input resetn,   // synchronous reset
    input in,
    output out);
    
    reg q0, q1, q2 ; 
    
    sub_module u0(clk, resetn, in, q0) ;
    sub_module u1(clk, resetn, q0, q1) ;
    sub_module u2(clk, resetn, q1, q2) ;
    sub_module u3(clk, resetn, q2, out) ;

endmodule

module sub_module (
    input clk, 
    input resetn, 
    input in,
    output out
);
    always @ (posedge clk) begin
        if (!resetn) out <= 0 ; 
        else out <= in ; 
    end
    
endmodule

题目链接:Exams/2014 q4b - HDLBits

module top_module (
    input [3:0] SW,
    input [3:0] KEY,
    output [3:0] LEDR
); //
    wire clk, E, L, w ;
    
    assign {w, L, E, clk} = KEY ; 
    
    sub_module u0(clk, w, SW[3], E, L, LEDR[3]) ;
    sub_module u1(clk, LEDR[3], SW[2], E, L, LEDR[2]) ;
    sub_module u2(clk, LEDR[2], SW[1], E, L, LEDR[1]) ;
    sub_module u3(clk, LEDR[1], SW[0], E, L, LEDR[0]) ;
  	
endmodule

module sub_module (
    input clk,
    input w, R, E, L,
    output Q
);
    wire mux1_out, mux2_out ; 
    
    assign mux1_out = E ? w : Q ; 
    assign mux2_out = L ? R : mux1_out ; 

    always @(posedge clk) begin
        Q <= mux2_out ; 
    end
    
endmodule

题目链接:Exams/ece241 2013 q12 - HDLBits

module top_module (
    input clk,
    input enable,
    input S,
    input A, B, C,
    output Z ); 
    
    wire [7:0] q ;
    wire [2:0] sel ; 
    
    assign sel = {A, B, C} ;
    
    sub_module u0(clk, enable, S, q[0]) ;
    
    genvar i ; 
    generate 
        for (i = 1 ; i <= 7 ; i = i + 1) begin : x 
            sub_module ui(clk, enable, q[i-1], q[i]) ;
        end
    endgenerate
    
    always @ (*) begin 
        case (sel)
            0 : Z <= q[0] ;
            1 : Z <= q[1] ;
            2 : Z <= q[2] ;
            3 : Z <= q[3] ;
            4 : Z <= q[4] ;
            5 : Z <= q[5] ;
            6 : Z <= q[6] ;
            7 : Z <= q[7] ;
        endcase
    end

endmodule

module sub_module (
    input clk, 
    input enable,
    input in,
    output out
);
    always @ (posedge clk) begin 
        if (enable) out <= in ; 
        else out <= out ; 
    end
endmodule
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