表:Genders
Column Name | Type |
---|---|
user_id | int |
gender | varchar |
编写一个解决方案以重新排列 Genders 表,使行按顺序在 ‘female’,‘other’ 和 ‘male’ 之间交替。同时每种性别按照 user_id 升序进行排序。
按 上述顺序 返回结果表。
返回结果格式如以下示例所示。
示例 1:
输入:
Genders 表:
user_id | gender |
---|---|
15 | other |
12 | female |
1 | other |
2 | female |
21 | other |
5 | male |
20 | male |
14 | other |
11 | male |
4 | male |
19 | male |
18 | other |
6 | other |
9 | female |
3 | female |
8 | female |
10 | male |
7 | other |
16 | male |
13 | female |
17 | female |
输出:
user_id | gender |
---|---|
2 | female |
1 | other |
4 | male |
3 | female |
6 | other |
5 | male |
8 | female |
7 | other |
10 | male |
9 | female |
14 | other |
11 | male |
12 | female |
15 | other |
16 | male |
13 | female |
18 | other |
19 | male |
17 | female |
21 | other |
20 | male |
解释:
女性:ID 2、3、8、9、12、13、17。
其他性别:ID 1、6、7、14、15、18、21。
男性:ID 4、5、10、11、16、19、20。
我们在 ‘female’,‘other’,‘male’ 之间交替排列表。
注意,每种性别都是按 user_id 升序排序的。
SELECT user_id, gender
FROM (
SELECT row_number() over (order by user_id) AS id, user_id, gender
FROM Genders
WHERE gender = 'female'
UNION ALL
SELECT row_number() over (order by user_id) AS id, user_id, gender
FROM Genders
WHERE gender = 'other'
UNION ALL
SELECT row_number() over (order by user_id) AS id, user_id, gender
FROM Genders
WHERE gender = 'male'
) AS one
ORDER BY id
| user_id | gender |
| ------- | ------ |
| 4 | male |
| 1 | other |
| 2 | female |
| 3 | female |
| 5 | male |
| 6 | other |
| 8 | female |
| 10 | male |
| 7 | other |
| 14 | other |
| 11 | male |
| 9 | female |
| 15 | other |
| 12 | female |
| 16 | male |
| 18 | other |
| 13 | female |
| 19 | male |
| 21 | other |
| 17 | female |
| 20 | male |
SELECT user_id, gender
FROM (
SELECT row_number() over (order by user_id) AS id, user_id, gender, 0 AS sort
FROM Genders
WHERE gender = 'female'
UNION ALL
SELECT row_number() over (order by user_id) AS id, user_id, gender, 1 AS sort
FROM Genders
WHERE gender = 'other'
UNION ALL
SELECT row_number() over (order by user_id) AS id, user_id, gender, 2 AS sort
FROM Genders
WHERE gender = 'male'
) AS one
ORDER BY id, sort
| user_id | gender |
| ------- | ------ |
| 2 | female |
| 1 | other |
| 4 | male |
| 3 | female |
| 6 | other |
| 5 | male |
| 8 | female |
| 7 | other |
| 10 | male |
| 9 | female |
| 14 | other |
| 11 | male |
| 12 | female |
| 15 | other |
| 16 | male |
| 13 | female |
| 18 | other |
| 19 | male |
| 17 | female |
| 21 | other |
| 20 | male |
SELECT *
FROM Genders
ORDER BY row_number() over(partition by gender order by user_id),
case when gender = 'female' then 1
when gender = 'male' then 3
else 2 end
直接使用 order by gender 是不行的,female-male-other 的顺序不符合要求 female-other-male,刚好可以使用长度倒序去做
SELECT *
FROM genders
ORDER BY row_number() over(partition by gender order by user_id),
length(gender) desc