将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。?
示例 1:
输入:l1 = [1,2,4], l2 = [1,3,4]
输出:[1,1,2,3,4,4]
示例 2:
输入:l1 = [], l2 = []
输出:[]
示例 3:
输入:l1 = [], l2 = [0]
输出:[0]
?
提示:
两个链表的节点数目范围是 [0, 50]
-100 <= Node.val <= 100
l1 和 l2 均按 非递减顺序 排列
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode() {}
* ListNode(int val) { this.val = val; }
* ListNode(int val, ListNode next) { this.val = val; this.next = next; }
* }
*/
class Solution
{
public ListNode mergeTwoLists(ListNode list1, ListNode list2)
{
if(list1 == null)
{
return list2;
}
else if(list2 == null)
{
return list1;
}
else if(list1.val > list2.val)
{
list2.next = mergeTwoLists(list1, list2.next);
return list2;
}
else
{
list1.next = mergeTwoLists(list2, list1.next);
return list1;
}
}
}