LeetCode //C - 283. Move Zeroes

283. Move Zeroes

Given an integer array nums, move all 0’s to the end of it while maintaining the relative order of the non-zero elements.

Note that you must do this in-place without making a copy of the array.
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Example 1:

Input: nums = [0,1,0,3,12]
Output: [1,3,12,0,0]

Example 2:

Input: nums = [0]
Output: [0]

Constraints:

• $1<=nums.length<=10^4$
• $?2^{31}<=nums[i]<=2^{31}?1$

From: LeetCode
Link: 283. Move Zeroes

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Solution:

Ideas：

• We iterate through the array with a for loop.
• If an element is not zero, we move it to the insertPos index and increment insertPos.
• After all non-zero elements are moved to the front, we fill the rest of the array with zeros, starting from insertPos to the end of the array.

Code:

void moveZeroes(int* nums, int numsSize) {
    int insertPos = 0;  // This will keep track of the position where we need to insert the next non-zero element.
    for (int i = 0; i < numsSize; i++) {
        if (nums[i] != 0) {
            nums[insertPos++] = nums[i];  // Move non-zero elements to the front and increment insertPos.
        }
    }
    while (insertPos < numsSize) {
        nums[insertPos++] = 0;  // Fill the remaining array with zeroes.
    }
}