????????死锁(Deadlock)是在并发计算中的一种状态,其中两个或多个进程无法继续执行,因为每个进程都在等待另一个进程释放所占用的资源。这种情况通常发生在系统中的资源分配过程中,其中每个进程都占用一些资源,并且正在等待其他进程释放它们所占用的资源,从而导致所有进程都无法继续执行。?
#include <stdio.h>
#include <pthread.h>
#include <unistd.h>
// 全局变量,所有的线程都共享这一份资源。
int tickets = 1000;
// 创建一个互斥量
pthread_mutex_t mutex;
void * sellticket(void * arg) {
// 卖票
while(1) {
// 加锁
pthread_mutex_lock(&mutex);
pthread_mutex_lock(&mutex);
if(tickets > 0) {
usleep(6000);
printf("%ld 正在卖第 %d 张门票\n", pthread_self(), tickets);
tickets--;
}else {
// 解锁
pthread_mutex_unlock(&mutex);
break;
}
// 解锁
pthread_mutex_unlock(&mutex);
pthread_mutex_unlock(&mutex);
}
return NULL;
}
int main() {
// 初始化互斥量
pthread_mutex_init(&mutex, NULL);
// 创建3个子线程
pthread_t tid1, tid2, tid3;
pthread_create(&tid1, NULL, sellticket, NULL);
pthread_create(&tid2, NULL, sellticket, NULL);
pthread_create(&tid3, NULL, sellticket, NULL);
// 回收子线程的资源,阻塞
pthread_join(tid1, NULL);
pthread_join(tid2, NULL);
pthread_join(tid3, NULL);
pthread_exit(NULL); // 退出主线程
// 释放互斥量资源
pthread_mutex_destroy(&mutex);
return 0;
}
#include <stdio.h>
#include <pthread.h>
#include <unistd.h>
// 创建2个互斥量
pthread_mutex_t mutex1, mutex2;
void * workA(void * arg) {
pthread_mutex_lock(&mutex1);
sleep(1);
pthread_mutex_lock(&mutex2);
printf("workA....\n");
pthread_mutex_unlock(&mutex2);
pthread_mutex_unlock(&mutex1);
return NULL;
}
void * workB(void * arg) {
pthread_mutex_lock(&mutex2);
sleep(1);
pthread_mutex_lock(&mutex1);
printf("workB....\n");
pthread_mutex_unlock(&mutex1);
pthread_mutex_unlock(&mutex2);
return NULL;
}
int main() {
// 初始化互斥量
pthread_mutex_init(&mutex1, NULL);
pthread_mutex_init(&mutex2, NULL);
// 创建2个子线程
pthread_t tid1, tid2;
pthread_create(&tid1, NULL, workA, NULL);
pthread_create(&tid2, NULL, workB, NULL);
// 回收子线程资源
pthread_join(tid1, NULL);
pthread_join(tid2, NULL);
// 释放互斥量资源
pthread_mutex_destroy(&mutex1);
pthread_mutex_destroy(&mutex2);
return 0;
}
/*
读写锁的类型 pthread_rwlock_t
int pthread_rwlock_init(pthread_rwlock_t *restrict rwlock, const pthread_rwlockattr_t *restrict attr);
int pthread_rwlock_destroy(pthread_rwlock_t *rwlock);
int pthread_rwlock_rdlock(pthread_rwlock_t *rwlock);
int pthread_rwlock_tryrdlock(pthread_rwlock_t *rwlock);
int pthread_rwlock_wrlock(pthread_rwlock_t *rwlock);
int pthread_rwlock_trywrlock(pthread_rwlock_t *rwlock);
int pthread_rwlock_unlock(pthread_rwlock_t *rwlock);
案例:8个线程操作同一个全局变量。
3个线程不定时写这个全局变量,5个线程不定时的读这个全局变量
*/
#include <stdio.h>
#include <pthread.h>
#include <unistd.h>
// 创建一个共享数据
int num = 1;
// pthread_mutex_t mutex;
pthread_rwlock_t rwlock;
void * writeNum(void * arg) {
while(1) {
pthread_rwlock_wrlock(&rwlock);
num++;
printf("++write, tid : %ld, num : %d\n", pthread_self(), num);
pthread_rwlock_unlock(&rwlock);
usleep(100);
}
return NULL;
}
void * readNum(void * arg) {
while(1) {
pthread_rwlock_rdlock(&rwlock);
printf("===read, tid : %ld, num : %d\n", pthread_self(), num);
pthread_rwlock_unlock(&rwlock);
usleep(100);
}
return NULL;
}
int main() {
pthread_rwlock_init(&rwlock, NULL);
// 创建3个写线程,5个读线程
pthread_t wtids[3], rtids[5];
for(int i = 0; i < 3; i++) {
pthread_create(&wtids[i], NULL, writeNum, NULL);
}
for(int i = 0; i < 5; i++) {
pthread_create(&rtids[i], NULL, readNum, NULL);
}
// 设置线程分离
for(int i = 0; i < 3; i++) {
pthread_detach(wtids[i]);
}
for(int i = 0; i < 5; i++) {
pthread_detach(rtids[i]);
}
pthread_exit(NULL);
pthread_rwlock_destroy(&rwlock);
return 0;
}