双端队列(deque,全名double-ended queue)是一种具有队列和栈性质的线性数据结构。双端队列也拥有两端:队首(front)、队尾(rear),但与队列不同的是,插入操作在两端(队首和队尾)都可以进行,删除操作也一样。
双端队列的数据存储结构可以是顺序表,也可以是链表,即顺序双端队列和链双端队列。
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双端队列ADT(抽象数据类型)一般提供以下接口:
Deque() 创建双端队列
insert(item) 向队首插入项
append(item) 向队尾插入项
popFront() 返回队首的项,并从双端队列中删除该项
pop() 返回队尾的项,并从双端队列中删除该项
isEmpty() 判断双端队列是否为空
size() 返回双端队列中项的个数
get(index) 返回对列中的对象
show() 对象遍历
操作示意图:
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顺序双端队列是使用顺序表存储数据的双端队列,Python 中的列表元组都属于顺序表,下面使用列表来存储数据,实现顺序双端队列。
class SeQueue(object):
def __init__(self):
self.__members = list()
def isEmpty(self):
return not len(self.__members)
def show(self):
if self.isEmpty():
return
for member in self.__members:
if self.__members.index(member) != len(self.__members) - 1:
print(member, end=',')
else:
print(member)
def insert(self, data):
self.__members.insert(0, data)
def append(self, data):
self.__members.append(data)
def popFront(self):
if self.isEmpty():
return
return self.__members.pop(0)
def pop(self):
if self.isEmpty():
return
return self.__members.pop()
def size(self):
return len(self.__members)
def check(self, index):
if index < 0 or index > len(self.__members) - 1:
raise IndexError
return self.__members[index]
使用
if? name?== ' main':
sdq = SeQueue()
print("isEmpty: ", sdq.isEmpty())
sdq.show()
sdq.insert('x')
sdq.insert('z')
sdq.append(10)
sdq.append(20)
sdq.show()
print(sdq.popFront())
print(sdq.pop())
sdq.show()
print("sequence double queue length: ", sdq.size())
print("index member is: ", sdq.check(2))
链双端队列是使用链表存储数据的双端队列,链表是逻辑有序的,由一个一个的节点构成,所以先声明一个创建节点的类。
# coding=utf-8
class Node(object):
"""
链双端,节点对象类
"""
def __init__(self, data):
self.data = data
self.next = None
class LinkQueue(object):
"""
链表
"""
def __init__(self):
self.__head = None
def isEmpty(self):
return not self.__head
def show(self):
if self.isEmpty():
return
cur = self.__head
while cur is not None:
if cur.next is not None:
print(cur.data, end=',')
else:
print(cur.data)
cur = cur.next
def insert(self, data):
node = Node(data)
node.next = self.__head
self.__head = node
def append(self, data):
if self.isEmpty():
self.insert(data)
return
node = Node(data)
cur = self.__head
while cur.next is not None:
cur = cur.next
cur.next = node
def popFront(self):
if self.isEmpty():
return
cur = self.__head
self.__head = self.__head.next
return cur.data
def pop(self):
if self.isEmpty():
return
cur = self.__head
prev = None
while cur.next is not None:
prev = cur
cur = cur.next
if cur == self.__head:
self.__head = self.__head.next
return
prev.next = cur.next
return cur.data
def size(self):
size = 0
cur = self.__head
while cur is not None:
size += 1
cur = cur.next
return size
def get(self, index):
if index < 0 or index >= self.size():
raise IndexError
cur = self.__head
for _ in range(index):
cur = cur.next
return cur.data
from collections import deque
class Deque:
def __init__(self):
self.items = deque()
def insert(self, item):
self.items.appendleft(item)
def append(self, item):
self.items.append(item)
def show(self):
if self.isEmpty():
return
for index, value in enumerate(self.items):
if index != len(self.items) - 1:
print(self.items.__getitem__(index), end=',')
else:
print(self.items.__getitem__(index))
def popFront(self):
return self.items.popleft()
def pop(self):
return self.items.pop()
def isEmpty(self):
return self.size() == 0
def size(self):
return len(self.items)
def get(self, index):
self.items.__getitem__(index)
举例
ldq = Deque()
# print("isEmpty: ", ldq.isEmpty())
# ldq.show()
ldq.insert('X')
ldq.insert('Y')
ldq.insert('Z')
ldq.append(100)
ldq.append(200)
ldq.append(300)
ldq.show()
# print(ldq.popFront())
# print(ldq.pop())
# ldq.show()
print("link queue length: ", ldq.size())
print("index member is: ", ldq.get(2))
输出
Z,Y,X,100,200,300
link queue length: 6
index member is: None
算法:回文(palindrome)是正读反读都一样的单词或句子,是一种修辞方式和文字游戏。
举例:
madam
able was i ere i saw elba
# 中文
花非花
人人为我、我为人人
如果要实现一个 回文验证算法(验证一个给定的字符串是否为回文),使用Deque类将非常容易:将字符串存储到双端队列,同时取出首尾字符并比较是否相等,只要有一对字符不等,则该字符串不是回文;若全部相等,则该字符串为回文。具体代码如下:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
def palchecker(aString):
chardeque = Deque()
for ch in aString:
chardeque.insert(ch)
while chardeque.size() > 1:
first = chardeque.popFront()
last = chardeque.pop()
if first != last:
return False
return True
if __name__ == '__main__':
str1 = 'able was i ere i saw elba'
print('"%s" is%s palindrome' % (str1, '' if palchecker(str1) else ' not'))
str2 = u'人人为我、我为人人'
print(u'"%s"%s是回文' % (str2, u'' if palchecker(str2) else u'不'))
str3 = u"What's wrong 怎么啦"
print(u'"%s"%s是回文' % (str3, u'' if palchecker(str3) else u'不'))