// 递归实现排列型枚举
#include<iostream>
using namespace std;
const int N = 10;
int state[N], n;
bool bis[N];
void dfs(int u)
{
if (u == n + 1)
{
for (int i = 1; i <= n; ++i)
cout << state[i] << " \n"[i == n];
return;
}
for (int i = 1; i <= n; ++i)
{
if (!bis[i])
{
state[u] = i;
bis[i] = true;
dfs(u + 1);
bis[i] = false;
}
}
}
int main()
{
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
cin >> n;
dfs(1);
return 0;
}