第五题 顺序打印ABC
依然是,一个协程打印A,一个协程打印B,一个协程打印C。按照上一题左右括号的例子,我们来试一下这题~
直接上代码:
package main
import (
"fmt"
"sync"
)
func main() {
for {
times := 1
c := make(chan struct{})
d := make(chan struct{})
var wg sync.WaitGroup
wg.Add(1)
go printA(c, times)
go printB(c, &wg, d)
go printC(d, &wg)
wg.Wait()
}
}
func printA(c chan struct{}, times int) {
defer close(c)
for i := 0; i < times; i++ {
fmt.Print("A")
c <- struct{}{}
}
}
func printB(c chan struct{}, wg *sync.WaitGroup, d chan struct{}) {
for range c {
fmt.Print("B")
d <- struct{}{}
}
close(d)
}
func printC(d chan struct{}, wg *sync.WaitGroup) {
defer wg.Done()
for range d {
fmt.Print("C")
}
}
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