Calculate?a+b?and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Each input file contains one test case. Each case contains a pair of integers?a?and?b?where??106≤a,b≤106. The numbers are separated by a space.
For each test case, you should output the sum of?a?and?b?in one line. The sum must be written in the standard format.
-1000000 9
-999,991
#include <stdio.h>
#include <math.h>
int main()
{
int a,b;
scanf("%d %d",&a,&b);
int sum=a+b;
char arr[12];
int i=0;
int cnt=0;
if(sum>0)
{
while(sum){
arr[i++]=sum%10+'0';
sum/=10;
cnt++;
if(cnt%3==0 && sum)
arr[i++]=',';
}
while(i>0){
printf("%c",arr[--i]);
}
} else if(sum<0){
sum=abs(sum);
while(sum){
arr[i++]=sum%10+'0';
sum/=10;
cnt++;
if(cnt%3==0 && sum)
arr[i++]=',';
}
printf("-");
while(i>0){
printf("%c",arr[--i]);
}
} else
printf("%d",sum);
return 0;
}
?用自己的现有知识琢磨出来的,一定还有其它方法。