字符串中第二多的字母

?

#include <stdio.h>
void atoA(char in[]){
    int i=0;
    while (in[i]!='\0'){
        if(in[i]>='a'&&in[i]<='z'){
            in[i]-=32;
        }
        i++;
    }
}
void find(char in[],int out[]){
    int i=0;
    while (in[i]!='\0'){
        if(in[i]>='A'&&in[i]<='Z'){
            out[in[i]-65]++;
        }
        i++;
    }
}
int second(int a[],char q[]){
    int g=0;
    int max=0;
    int second=0;
    for (int i = 0; i < 26;i++) {
        if(a[i]>max){
            max=a[i];
        }
    }
    for (int i = 0; i < 26;i++) {
        if(a[i]==max){
            a[i]=0;
        }
    }
    for (int i = 0; i < 26;i++) {
        if(second<a[i]){
            second=a[i];
        }
    }
    int j=0;
    for (int i = 0; i < 26;i++) {
        if(a[i]==second){
            q[j]=i+65;
            j++;
        }
    }
    q[j]='\0';
    return g;
}
int main(){
    char a[501]={0};
    char q[26]={0};
    int count[26]={0};
    fgets(a,500,stdin);
    atoA(a);
    find(a,count);
    second(count,q);
    int i=0;
    while (a[i] != '\0')
    {
        int j = 0;
        while (q[j] != '\0')
        {
            if (a[i] == q[j])
            {
                printf("%c+%c:%d",q[j],(char)(q[j]+32),count[q[j]-65]);
                return 0;
            }
            j++;
        }
        i++;
    }
    return 0;
}