class Solution {
public:
bool lemonadeChange(vector<int>& bills) {
vector<int> restBill = {0, 0, 0, 0};
for (int i = 0; i < bills.size(); i++) {
restBill[bills[i] / 5 - 1]++;
if (bills[i] == 5) continue;
if (bills[i] == 10) {
if (restBill[0] == 0) return false;
restBill[0]--;
}
if (bills[i] == 20) {
if (restBill[1] > 0 && restBill[0] > 0) {
restBill[1]--;
restBill[0]--;
continue;
}
if (restBill[0] >= 3) {
restBill[0] -= 3;
continue;
}
return false;
}
}
return true;
}
};
?其实我自己写的这段代码有问题:一开始想用数组直接存放钱的数目,但其实这个20块钱不是索引为2,在数组中的位置是3,但20不涉及到找零问题,这里不影响。最好还是按下面写:
class Solution {
public:
bool lemonadeChange(vector<int>& bills) {
int five = 0, ten = 0, twenty = 0;
for (int bill : bills) {
// 情况一
if (bill == 5) five++;
// 情况二
if (bill == 10) {
if (five <= 0) return false;
ten++;
five--;
}
// 情况三
if (bill == 20) {
// 优先消耗10美元,因为5美元的找零用处更大,能多留着就多留着
if (five > 0 && ten > 0) {
five--;
ten--;
twenty++; // 其实这行代码可以删了,因为记录20已经没有意义了,不会用20来找零
} else if (five >= 3) {
five -= 3;
twenty++; // 同理,这行代码也可以删了
} else return false;
}
}
return true;
}
};
代码来源:代码随想录?
按照h降序,k升序排序。
class Solution {
private:
static bool cmp(const vector<int>& a, const vector<int>& b) {
if (a[0] == b[0]) return a[1] < b[1];
return a[0] > b[0];
}
public:
vector<vector<int>> reconstructQueue(vector<vector<int>>& people) {
sort(people.begin(), people.end(), cmp);
vector<vector<int>> res;
for (int i = 0; i < people.size(); i++) {
int position = people[i][1];
res.insert(res.begin() + position, people[i]);
}
return res;
}
};
class Solution {
private:
static bool cmp(vector<int>& a, vector<int>& b) {
return a[0] < b[0];
}
public:
int findMinArrowShots(vector<vector<int>>& points) {
sort(points.begin(), points.end(), cmp);
int result = 1;
for (int i = 1; i < points.size(); i++) {
if (points[i][0] > points[i - 1][1]) result++;
else {
points[i][1] = min(points[i - 1][1], points[i][1]);
}
}
return result;
}
};