记录一次改代码的挣扎经历:
????????看了几篇关于DCT频域的深度模型文献,尤其是21年FcaNet:基于DCT 的attention model,咱就是说想试试将我模型的输入改为分组的DCT系数,然后就开始下面的波折了。
第一次尝试:
????????我直接调用了库函数,然后出现问题了:这个库函数是应用在numpy数组上,得在CPU上处理。
from scipy.fftpack import dct, idct
...
dct_block = dct(dct(block, axis=2, norm='ortho'), axis=3, norm='ortho') # [B,C,k,k]
...
block = idct(idct(dct_block, axis=2, norm='ortho'), axis=3, norm='ortho') # [B,C,k,k]
第二次尝试:
????????好吧,我先把数据调回CPU,处理后,再调回GPU,又有新问题了:这样做(将block从GPU转移至CPU)torch类型张量转换为numpy数组时,torch张量的梯度无法保存。
# 图像分块
...
# 将块转移到 CPU
block_cpu = block.cpu() # [B,C,k,k]
# 在 CPU 上对块应用 DCT
dct_block_np = dct(dct(block_cpu.numpy(), axis=2, norm='ortho'), axis=3, norm='ortho') # [B,C,k,k]
# 将结果传输回 GPU
dct_block = torch.from_numpy(dct_block_np).to(image.device) # [B,C,k,k]
...
# 将块转移到 CPU
dct_block_cpu = dct_block.cpu()
# 在 CPU 上对块应用逆 DCT
block_np = idct(idct(dct_block_cpu.numpy(), axis=2, norm='ortho'), axis=3, norm='ortho')
# 将结果传输回 GPU
block = torch.from_numpy(block_np).to(dct_block.device) # [B,C,k,k]
?第三次尝试:
? ? ? ? 根据报错提醒,我进行以下改进,将block_cpu.numpy -> block_cpu.detach.numpy(),即忽略掉torch类型张量带着的梯度信息,哈哈,这样一改,梯度就丢失了,模型就不能反向传播进行更新训练了。
# 图像分块
...
# 将块转移到 CPU
block_cpu = block.cpu() # [B,C,k,k]
# 在 CPU 上对块应用 DCT
dct_block_np = dct(dct(block_cpu.numpy(), axis=2, norm='ortho'), axis=3, norm='ortho') # [B,C,k,k]
# 将结果传输回 GPU
dct_block = torch.from_numpy(dct_block_np).to(image.device) # [B,C,k,k]
...
# 将块转移到 CPU
dct_block_cpu = dct_block.cpu()
# 在 CPU 上对块应用逆 DCT
block_np = idct(idct(dct_block_cpu.detach.numpy(), axis=2, norm='ortho'), axis=3, norm='ortho')
# 将结果传输回 GPU
block = torch.from_numpy(block_np).to(dct_block.device) # [B,C,k,k]
第四次尝试:
? ? ? ? CPU上库函数不好用,那我自己写(借鉴)DCT变换的函数嘛,DCT就是输入k*k图像关于k*k个余弦基函数的加权和嘛:
?别人写的的8 x 8d的DCT和IDCT的实现:
class DCT8X8(nn.Module):
""" Discrete Cosine Transformation
Input:
image(tensor): batch x height x width
Output:
dcp(tensor): batch x height x width
"""
def __init__(self):
super(DCT8X8, self).__init__()
tensor = np.zeros((8, 8, 8, 8), dtype=np.float32)
for x, y, u, v in itertools.product(range(8), repeat=4):
tensor[x, y, u, v] = np.cos((2 * x + 1) * u * np.pi / 16) * np.cos((2 * y + 1) * v * np.pi / 16)
alpha = np.array([1. / np.sqrt(2)] + [1] * 7)
self.tensor = nn.Parameter(torch.from_numpy(tensor).float())
self.scale = nn.Parameter(torch.from_numpy(np.outer(alpha, alpha) * 0.25).float())
def forward(self, image):
image = image - 128
result = self.scale * torch.tensordot(image, self.tensor, dims=2)
result.view(image.shape)
return result
class IDCT8X8(nn.Module):
""" Inverse discrete Cosine Transformation
Input:
dcp(tensor): batch x height x width
Output:
image(tensor): batch x height x width
"""
def __init__(self):
super(IDCT8X8, self).__init__()
alpha = np.array([1. / np.sqrt(2)] + [1] * 7)
self.alpha = nn.Parameter(torch.from_numpy(np.outer(alpha, alpha)).float())
tensor = np.zeros((8, 8, 8, 8), dtype=np.float32)
for x, y, u, v in itertools.product(range(8), repeat=4):
tensor[x, y, u, v] = np.cos((2 * u + 1) * x * np.pi / 16) * np.cos((2 * v + 1) * y * np.pi / 16)
self.tensor = nn.Parameter(torch.from_numpy(tensor).float())
def forward(self, image):
image = image * self.alpha
result = 0.25 * torch.tensordot(image, self.tensor, dims=2) + 128
result.view(image.shape)
return result
我根据上述改的任意block_size的DCT和IDCT:
class DCTCustom(nn.Module):
"""Customizable Discrete Cosine Transformation
Input:
image(tensor): batch x height x width
Output:
dct(tensor): batch x height x width
"""
def __init__(self, input_size=8):
super(DCTCustom, self).__init__()
self.input_size = input_size
tensor = np.zeros((input_size, input_size, input_size, input_size), dtype=np.float32)
for x, y, u, v in itertools.product(range(input_size), repeat=4):
tensor[x, y, u, v] = np.cos((2 * x + 1) * u * np.pi / (2 * input_size)) * np.cos((2 * y + 1) * v * np.pi / (2 * input_size))
alpha = np.array([1. / np.sqrt(2)] + [1] * (input_size - 1))
self.tensor = nn.Parameter(torch.from_numpy(tensor).float())
self.scale = nn.Parameter(torch.from_numpy(np.outer(alpha, alpha) * 0.25).float())
def forward(self, image):
image = image - 128
result = self.scale * torch.tensordot(image, self.tensor, dims=2)
result = result.view(image.shape) # Corrected line
return result
class IDCTCustom(nn.Module):
""" Inverse discrete Cosine Transformation
Input:
dcp(tensor): batch x height x width
Output:
image(tensor): batch x height x width
"""
def __init__(self, block_size=8):
super(IDCTCustom, self).__init__()
self.block_size = block_size
# Compute alpha coefficients
alpha = np.array([1. / np.sqrt(2)] + [1] * (block_size - 1))
self.alpha = nn.Parameter(torch.from_numpy(np.outer(alpha, alpha)).float())
# Compute tensor for IDCT
tensor = np.zeros((block_size, block_size, block_size, block_size), dtype=np.float32)
for x, y, u, v in itertools.product(range(block_size), repeat=4):
tensor[x, y, u, v] = np.cos((2 * u + 1) * x * np.pi / (2 * block_size)) * np.cos(
(2 * v + 1) * y * np.pi / (2 * block_size)
)
self.tensor = nn.Parameter(torch.from_numpy(tensor).float())
def forward(self, image):
if image.shape[-2] % self.block_size != 0 or image.shape[-1] % self.block_size != 0:
raise ValueError("Input dimensions must be divisible by the block size.")
# Apply IDCT
image = image * self.alpha
result = 0.25 * torch.tensordot(image, self.tensor, dims=2) + 128
result = result.view(image.shape)
return result
? ? ? ? 不出意外的话,问题又出现了,我对一个torch.ones((2,3,k,k))的张量进行DCT,再IDCT恢复。当k=8时(即block_size=8x8)时,能够完全恢复,但当k!=8(=16、32)时,经IDCT后无法恢复原始输入,懵。
第五次尝试(hh):
? ? ? ? 突然!我发现了torch内置的DCT函数!可以再GPU上实现DCT。
import torch_dct as dct
# 图像分块 # [B,C,H,W]
... # [B,C,k,k]
# dct
block = dct.dct_2d(block) # [B,C,k,k]
...
# idct
block = dct.idct_2d(block) # [B,C,k,k]
?然后又有问题了:
? ? ? ? 我的模型开始训练后,我发现我的每个epoch的loss都为NAN...
????????然后我打印了DCT输出,发现DCT系数长这个样子,CNN不高兴好好训练吧。
????????我们再想想办法将输入数据归一化到范围[0, 1]或[-1, 1]之间,再喂给CNN吧。