目录
????????11)查询没学过"张三"老师讲授的任一门课程的学生姓名
????????12)查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
????????13)检索" 01 "课程分数小于 60,按分数降序排列的学生信息
????????14)按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
SELECT
?? ?s.*,
?? ?c.cname,
?? ?t.tname,
?? ?sc.score?
FROM
?? ?t_mysql_teacher t,
?? ?t_mysql_course c,
?? ?t_mysql_student s,
?? ?t_mysql_score sc?
WHERE
?? ?t.tid = c.tid?
?? ?AND c.cid = sc.cid?
?? ?AND sc.sid = s.sid?
?? ?AND t.tname = '张三'
-- 没有学全
学全了有多少门:统计一共有多少门学科
统计每一个学生学了多少门SELECT
?? ?s.sid,
?? ?s.sname,
?? ?count( sc.score ) n?
FROM
?? ?t_mysql_student s
?? ?LEFT JOIN t_mysql_score sc ON s.sid = sc.sid?
GROUP BY
?? ?s.sid,
?? ?s.sname?
HAVING
?? ?n < (SELECT count( 1 ) FROM t_mysql_course)
没学过: 子查询
SELECT
?? ?s.sid,
?? ?s.sname?
FROM
?? ?t_mysql_score sc,
?? ?t_mysql_student s?
WHERE
?? ?s.sid = sc.sid?
?? ?AND sc.cid NOT IN ( SELECT cid FROM t_mysql_course c, t_mysql_teacher t?
?? ?WHERE c.tid = t.tid AND t.tname = '张三' )?
GROUP BY
?? ?s.sid,
?? ?s.sname
SELECT
?? ?s.sid,
?? ?s.sname,
?? ?AVG( sc.score ) n?
FROM
?? ?t_mysql_student s,
?? ?t_mysql_score sc?
WHERE
?? ?s.sid = sc.sid?
?? ?AND sc.score < 60?
GROUP BY
?? ?s.sid,
?? ?s.sname
SELECT
?? ?s.*,
?? ?sc.score?
FROM
?? ?t_mysql_student s,
?? ?t_mysql_score sc?
WHERE
?? ?s.sid = sc.sid?
?? ?AND sc.cid = '01'?
?? ?AND sc.score < 60?
ORDER BY
?? ?sc.score DESC
平均 GROUP BY
从高到低 ORDER BY
所有学生的所有课程的成绩
姓名 语文 数学 英语 平均成绩select
?s.sid,
?s.sname,
?sum(if(sc.cid = '01',sc.score,0)) 语文,
?sum(if(sc.cid = '02',sc.score,0)) 数学,
?sum(if(sc.cid = '03',sc.score,0)) 英语,
?ROUND(AVG(sc.score),2) 平均分
from
? t_mysql_score sc
RIGHT JOIN t_mysql_student s on sc.sid = s.sid
GROUP BY
?? ?s.sid,
?? ?s.sname
-- GROUP BY
-- 大量使用函数SELECT
?? ?c.cid,
?? ?c.cname,
?? ?count(sc.sid) 人数,
?? ?max(sc.score) 最高分,
?? ?min(sc.score) 最低分,
?? ?ROUND(avg(sc.score),2) 平均分,
?? ?CONCAT(ROUND(sum(if(sc.score >= 60,1,0))/(select count(1) from t_mysql_student)*100,2),'%') 及格率,
?? ?CONCAT(ROUND(sum(if(sc.score >= 70 and sc.score < 80,1,0))/(select count(1) from t_mysql_student)*100,2),'%') 中等,
?? ?CONCAT(ROUND(sum(if(sc.score >= 80 and sc.score < 90,1,0))/(select count(1) from t_mysql_student)*100,2),'%') 优良,
?? ?CONCAT(ROUND(sum(if(sc.score >= 90,1,0))/(select count(1) from t_mysql_student)*100,2),'%') 优秀率
FROM
?? ?t_mysql_score sc
?? ?LEFT JOIN t_mysql_course c ON sc.cid = c.cid?
GROUP BY
?? ?c.cid,
?? ?c.cname