题记(20)--Primary Arithmetic

目录

一、题目内容

二、输入描述

三、输出描述

四、输入输出示例

五、完整C语言代码

一、题目内容

Children are taught to add multi-digit numbers from right-to-left one digit at a time. Many find the "carry" operation - in which a 1 is carried from one digit position to be added to the next - to be a significant challenge. Your job is to count the number of carry operations for each of a set of addition problems so that educators may assess their difficulty.

二、输入描述

Each line of input contains two unsigned integers less than 10 digits.

三、输出描述

?For each line of input except the last you should compute and print the number of carry operations that would result from adding the two numbers, in the format shown below.

四、输入输出示例

输入：

123 456
555 555
123 594
0 0

输出：

NO carry operation.
3 carry operations.
1 carry operation.

五、完整C语言代码

AC代码~

#include<stdio.h>
int main() {
    int a[10];
    int b[10];
    int x, y;
    while (scanf("%d%d", &x, &y) != EOF) {
        if (x == 0 && y == 0)
            break;
        int time = 0;
        int i = 0, j = 0;
        while (x != 0) {
            a[i++] = x % 10;
            x /= 10;
        }
        while (y != 0) {
            b[j++] = y % 10;
            y /= 10;
        }
        int carry = 0;
        int min_len = i > j ? j : i;
        for (int k = 0; k < min_len - 1; k++) {
            int tmp = a[k] + b[k] + carry;
            if (tmp >= 10) {
                time++;
                carry = tmp / 10;
            } else
                carry = 0;
        }
        int tmp = a[min_len - 1] + b[min_len - 1] + carry;
        if (tmp >= 10)
            time++;
        if (time == 0)
            printf("NO carry operation.\n");
        else if (time == 1)
            printf("1 carry operation.\n");
        else
            printf("%d carry operations.\n", time);
    }
    return 0;
}