#include<bits/stdc++.h>
using namespace std;
void merge(int* a, int low, int mid, int hight) //合并函数
{
int* b = new int[hight - low + 1]; //用 new 申请一个辅助函数
int i = low, j = mid + 1, k = 0; // k为 b 数组的小标
while (i <= mid && j <= hight)
{
if (a[i] <= a[j])
{
b[k++] = a[i++]; //按从小到大存放在 b 数组里面
}
else
{
b[k++] = a[j++];
}
}
while (i <= mid) // j 序列结束,将剩余的 i 序列补充在 b 数组中
{
b[k++] = a[i++];
}
while (j <= hight)// i 序列结束,将剩余的 j 序列补充在 b 数组中
{
b[k++] = a[j++];
}
k = 0; //从小标为 0 开始传送
for (int i = low; i <= hight; i++) //将 b 数组的值传递给数组 a
{
a[i] = b[k++];
}
delete[]b; // 辅助数组用完后,将其的空间进行释放(销毁)
}
void mergesort(int* a, int low, int hight) //归并排序
{
if (low < hight)
{
int mid = (low + hight) / 2;
mergesort(a, low, mid); //对 a[low,mid]进行排序
mergesort(a, mid + 1, hight); //对 a[mid+1,hight]进行排序
merge(a, low, mid, hight); //进行合并操作
}
}
int main()
{
int n;
cin>>n;
int a[n];
for(int i=0; i<n; i++){
cin>>a[i];
}
mergesort(a,0,n-1);
for(int i=0; i<n; i++){
cout<<a[i]<<" ";
}
cout<<endl;
return 0;
}
输入样例:
5
3 1 2 4 5
输出样例:
1 2 3 4 5