string solve() {
cin >> n >> a >> b >> c;
if (a == c || b == c) return no;
for (int i = 0; i < n; i ++) {
if (a[i] == b[i]) {
if (a[i] != c[i]) return yes;
} else {
if (a[i] != c[i] && b[i] != c[i]) return yes;
}
}
return no;
}
ll C2(ll x) { return x * (x - 1) / 2; }
ll C3(ll x) { return x * (x - 1) * (x - 2) / 6; }
ll solve() {
cin >> n;
map<int, int> mp;
for (int i = 0; i < n; i ++) {
int x; cin >> x;
mp[x] ++;
}
ll res = 0, cnt = 0;
for (auto [x, y]: mp) {
if (y >= 2) res += C2(y) * cnt;
if (y >= 3) res += C3(y);
cnt += y;
}
return res;
}
前缀和
int n, m;
int a[N];
int l[N], r[N];
int L[N], R[N];
void solve() {
cin >> n;
for (int i = 1; i <= n; i ++) cin >> a[i];
L[n + 1] = 0;
r[1] = l[n] = 1;
for (int i = 2; i <= n - 1; i ++) {
l[i] = abs(a[i] - a[i - 1]);
r[i] = abs(a[i] - a[i + 1]);
if (l[i] < r[i]) l[i] = 1;
else r[i] = 1;
}
for (int i = 1; i <= n; i ++) R[i] = R[i - 1] + r[i];
for (int i = n; i >= 1; i --) L[i] = L[i + 1] + l[i];
cin >> m;
while (m --) {
int x, y; cin >> x >> y;
if (x < y) cout << R[y - 1] - R[x - 1] << endl;
else cout << L[y + 1] - L[x + 1] << endl;
}
}